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astraxan [27]
4 years ago
6

Use the graph of the function to evaluate f(2).

Mathematics
1 answer:
oee [108]4 years ago
6 0
Do you have the picture?
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The odds in favor of an event are 2:9 or 2/9. What are the odds against the event?
ddd [48]

Answer:

Odds against the events are 7/9.

Step-by-step explanation:

It is given that:

Odds in favor of event = 2 : 9 or 2/9

Let,

These odds are out of 1.

The odds against the event would be

Odds against = 1 - 2/9

Odds against = \frac{9-2}{9}

Odds against = \frac{7}{9}

Therefore,

Odds against the events are 7/9.

5 0
3 years ago
In factored form please help
Brilliant_brown [7]

Answer:

3rd option

Step-by-step explanation:

\frac{3x^2-3}{x^2-5x+4} ( factorise numerator and denominator )

3x² - 3 ← factor out 3 from each term

= 3(x² - 1²) ← x² - 1 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

x² - 1

= x² - 1²

= (x - 1)(x + 1) , then

3x² - 3 = 3²(x - 1)(x + 1) ← in factored form

--------------------------------

x² - 5x + 4

consider the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (- 5)

the factors are - 1 and - 4 , since

- 1 × - 4 = + 4 and - 1 - 4 = - 5 , then

x² - 5x + 4 = (x - 1)(x - 4)

then

\frac{3x^2-3}{x^2-5x+4} = \frac{3(x-1)(x+1)}{(x-1)(x-4)} ← in factored form

3 0
2 years ago
there are 657 lights on you set. on any given day 6 of them burn out and need to be replaced . if each light cost $45 how much d
Klio2033 [76]

Answer:

1890, total cost of lights per week

Step-by-step explanation:

The lights cost 45 dollars per bulb and 6 go out per day, 45×6=270

270 is the cost to replace the bulbs of one day.

270×7=1890.  1890 is the cost for a whole weeks worth of replacing these bulbs.

6 0
3 years ago
Which expression is equivalent to b^m•b^n<br> A. b^m-n<br> B. b^m•n<br> C. b^m÷n<br> D. b^m+n
Step2247 [10]
   
\displaystyle\\ &#10;\bold{b^m \times b^n = b^{m + n}~~~(D)}\\\\ &#10;\bold{\frac{b^m}{b^n}= b^{m - n}~~~~~~~~~(A)}\\\\ &#10;\bold{\Big(b^m \Big)^n = b^{m\times n}~~~~(B)}\\\\ &#10;\bold{\sqrt[\bold{n}]{\bold{b^m}} = b^{m\div n } ~~~~~~(C)}



6 0
3 years ago
My Homework Mr Thompson please help!!
Nady [450]

Answers:

  1. C) Factored form
  2. C) Standard form
  3. D) The y intercept is -8
  4. B) Two solutions: x = -5 or x = 5
  5. B) Apply square root to both sides

=========================================

Explanations:

  • For problems 1 and 2, there's not much to say other than you'll just have to memorize those terms. Standard form is ax^2+bx+c in general. The exponents count down 2,1,0. Factored form is where we have two or more factors multiplying with each other. Think of something like 21 = 7*3 showing that 7 and 3 are factors of 21.
  • For problem 3, the y intercept is the last value. It's the constant value. Plug in x = 0 and you'll get y = -8 as a result. The y intercept always occurs when x = 0.
  • In problem 4, we apply the square root to both sides to get x = -5 or x = 5. The plus or minus is needed. This is because (-5)^2 = 25.
  • In problem 5, we apply the square root to both sides to undo the squaring operation.
4 0
3 years ago
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