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3 years ago

Please help me out !! Asap

Mathematics

2 answers:

Paraphin [41]3 years ago

8 0

Answer:

(1,5)

Step-by-step explanation:

y = 4x+1

y = 2x+3

Set the two equations equal

4x+1 = 2x+3

Subtract 2x from each side

4x+1-2x = 2x+3-2x

2x+1 = 3

Subtract 1 from each side

2x+1-1 =3-1

2x=2

Divide by 2

2x/2 =2/2

x =1

Now find y

y =4x+1 = 4(1)+1 =4+1=5

(1,5)

igor_vitrenko [27]3 years ago

4 0

Answer:

4x + 1 is 3

2x + 3 is -1

Step-by-step explanation:

You might be interested in

Use the zero product property to find the solutions to the equation x2 – 13x + 30 = 0.

alukav5142 [94]

Answer:

The solutions to this quadratic equation are 10 and 3.

Step-by-step explanation:

1. Let's recall the formula for solving this type of equations, called quadratic equations:

x = ( - b +/- √ b² - 4ac)/ 2a

The equation given is x2 – 13x + 30 = 0,

where a = 1, b = - 13 and c = 30

Now replacing with the real values, we have

x = [ - (-13) +/- √ (-13)² - 4 * 1 * 30] / 2 * 1

x = [ 13 +/- √ 169 - 120] / 2

x = [13 +/- √ 49]/ 2

x = [ 13 +/- 7 ]/ 2

x₁ = 13 + 7/2 = 20/2 = 10

x₂ = 13 - 7/2 = 6/2 = 3

8 0

3 years ago

You work as a quality control inspector of shirts for a clothing manufacturing company. Today you examine one batch and 15% fail

Otrada [13]

Answer:

23%

Step-by-step explanation:

To find how many failed inspection, add together all the percentages:

15 + 5 + 3

= 23

So, 23% of the products failed inspection

5 0

2 years ago

Which of the following is a solution to 2cos2x − cos x − 1 = 0?

Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, $x = 0^{\circ}$

Step-by-step explanation:

Given that : $2\cos^2x -\cos x -1 =0$

Let $\cos x =y$

then our equation become;

$2y^2-y-1= 0$ .....[1]

A quadratic equation is of the form:

$ax^2+bx+c =0$ .....[2] where a, b and c are coefficient and the solution is given by;

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

$y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}$

Simplify:

$y = \frac{ 1 \pm \sqrt{1+8}}{4}$

$y = \frac{ 1 \pm \sqrt{9}}{4}$

$y = \frac{ 1 \pm 3}{4}$

$y = \frac{1+3}{4}$ and $y = \frac{1 -3}{4}$

Simplify:

y = 1 and $y = -\frac{1}{2}$

Substitute y = cos x we have;

$\cos x = 1$

⇒ $x = 0^{\circ}$

and

$\cos x = -\frac{1}{2}$

⇒ $x = 120^{\circ} \text{and} x = 240^{\circ}$

The solution set: $\{0^{\circ}, 120^{\circ} , 240^{\circ}\}$

Therefore, the solution for the given equation $2\cos^2x -\cos x -1 =0$ is, $0^{\circ}$

8 0

3 years ago

Read 2 more answers

Which ordered pair is not a solution of y = 2x + 1?

Dmitrij [34]

Answer:

(-1,1)

Step-by-step explanation:

All you have to do is plug it in the equation:

(x,y)

For (-1,1)

1=2(-1)+1

Simplify:

1=-1 but you know that 1≠-1 so (-1,1) is not it

For (3,7)

7=2(3)+1

Simplify:

7=7

For (-3,-5)

-5=2(-3)+1

-5=-5

Simplify:

For (0,1)

1=2(0)+1

1=1

7 0

3 years ago

Read 2 more answers

The city park department is planning to enclose a play area with fencing. One side of the area will be against an existing build

Oksanka [162]

Answer:

The maximum rectangular area will have the length 400 meters and width 200 meters with one side of the length against an existing building.

Step-by-step explanation:

From the given information;

The perimeter of a rectangle = 2 (L+B)

here;

L = the length of the side of the fence

B = the width of the fence

So; The perimeter of a rectangle = 2L+2B

we are also being told that;

One side of the area will be against an existing building

i.e

The perimeter of a rectangle is now = L + 2B = 800 meters

L = 800 - 2B

Similarly; Area of a rectangle = L × B

Area of a rectangle = ( 800 - 2B) × B

Area of a rectangle = 800B - 2B²

assuming A(B) to represent the Area;

Then the maximum area A'(B) = 0 ;

Thus,

A'(B) = 800 - 4B = 0

-4B = - 800

4B = 800

B = 200

Therefore; the maximum area have a width = 200 meters and a length 800 - 2(200) = 800 - 400 = 400 meters

3 0

3 years ago