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2 years ago

Find the area of the rectangle with vertices at the given points. You may find it helpful to sketch a graph.

1 answer:

3 0

It is 10 units². The difference between x and x is 5 and the difference between y and y is 2. 5 times 2 is 10. Hope this helps!

You might be interested in

How do I solve 5x - 4x^2

Sever21 [200]

Answer:

If you are asking,

5x - 4x^2=0

x(5-4x)=0

Either,

x=0

or,

5-4x=0

x=5/4

If factor,

5x - 4x^2

x(5-4x)

If difference,

5x - 4x^2

The same as they are not like terms.

7 0

2 years ago

I really need help guys can some one plz help me it's for 10 points

11111nata11111 [884]

Answer:

$\sqrt{8}----- 2units,2units$

$\sqrt{7} ------\sqrt{5}units,\sqrt{2}units$

$\sqrt{5}-------1unit,2units$

$3------2units, \sqrt{5}units$

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

$Formula: c^2=a^2+b^2$

1. $a=\sqrt{5}, b=\sqrt{2}$

Plug this into the formula.

$c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }$

The square here eliminates the roots.

$c=\sqrt{5+2}\\ c=\sqrt{7}$

2. $a=\sqrt{3}, b=4$

$c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}$

3. $a=2, b=\sqrt{5}$

$c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3$

4. $a=2, b=2$

$c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}$

5. $a=1, b=2$

$c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}$

7 0

3 years ago

What is the rate of interest on a loan of $2,000, for 284 days, if the amount of interest is $93.37, using the exact interest me

Viefleur [7K]

Answer: Option (c) is correct. Rate of interest = 6% p.a.

Step-by-step explanation:

Given that,

principal amount = $2000(loan)

time period = 284 days

interest amount (SI) = $93.37

we have to calculate the rate of interest (i),

Simple interest(SI) = principal amount × rate of interest (i) × time period

93.37 = 2000 × i × $\frac{284}{365}$

i = $\frac{34080.05}{568000}$

i = 0.06

i = 6%

3 0

2 years ago

7.5.5. I usually walk from home to work. This morning, I walked for 10 minutes until I was halfway to work. I then realized that

olya-2409 [2.1K]

Answer:

Given:

I usually walk from home to work. This morning, I walked for 10 minutes until I was halfway to work.

I then realized that I would be late if I kept walking.

I ran the rest of the way. I run twice as fast as I walk.

Find:

The number of minutes in total did it take me to get from home to work

Step-by-step explanation:

Had I kept walking, the second half of my trip would have taken 10 more minutes.

By doubling my speed for the second half of my trip,

I halved the amount of time it took me to finish.

So, the second half of my trip took 5 minutes, for a total trip time of 10+5 = 15 minutes.

The number of minutes in total did it take me to get from home to work is 15 minutes.

3 0

1 year ago

Read 2 more answers

Would anyone know how to do this

butalik [34]

Your answer will be 5xplus10

8 0

3 years ago