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3 years ago

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A right triangle has an area of 36 square units. If you draw scaled copies of this triangle using the scale factors in the table

, what will the areas of these scaled copies be? Please help me this is due 12:30

1 answer:

kolbaska11 [484]3 years ago

8 0

The answer that should be correct would be 5

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How many different ways can a 9-player baseball team be selected for an informal game if there are 25 available players? Which c

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1. The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag a

lapo4ka [179]

Answer:

Option d :18 bags of chips and 6 jars of salsa

Step-by-step explanation:

Given : The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag and salsa, which costs $4 per jar. The chips & salsa budget you are given totals $60.

Inequality : $2.5x+4y\leq 60$

Solution :

x represents chips

y represents salsa

Option a: 10 bags of chips and 2 jars of salsa

so, x = 10 and y =2

Putting values in inequality

$2.5(10)+4(2)\leq 60$

$25+8\leq 60$

$33\leq 60$

Hence it is correct.

Option b : 20 bags of chips and 2 jars of salsa

so, x = 20 and y =2

Putting values in inequality

$2.5(20)+4(2)\leq 60$

$50+8\leq 60$

$58\leq 60$

Hence it is correct.

Option c : 14 bags of chips and 5 jars of salsa

so, x = 14 and y =5

Putting values in inequality

$2.5(14)+4(5)\leq 60$

$35+20\leq 60$

$55\leq 60$

Hence it is correct.

Option d :18 bags of chips and 6 jars of salsa

so, x = 18 and y =6

Putting values in inequality

$2.5(18)+4(6)\leq 60$

$45+24\leq 60$

$69\geq 60$

Hence it is not correct since it violates the inequality

4 0

3 years ago

Read 2 more answers

A small combination lock on a suitcase has 55 wheels, each labeled with the 10 digits 0 to 9. How many 55 digit combinations ar

den301095 [7]

Suppose $a_n$ is the number of possible combinations for a suitcase with a lock consisting of $n$ wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for $n+1$ wheels, or $a_{n+1}$ is given recursively by the formula

$a_{n+1}=9a_n$

starting with $a_1=10$ (because you can start the combination with any one of the ten available digits 0 through 9).

For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).

By substitution, you have

$a_{n+1}=9a_n=9^2a_{n-1}=9^3a_{n-2}=\cdots=9^na_1=10\times9^n$

This means a lock with 55 wheels will have

$a_{55}=10\times9^{54}$

possible combinations (a number with 53 digits).

7 0

3 years ago

What property justifies this statement

Varvara68 [4.7K]

Answer:

B. SUBTRACTION PROPERTY OF EQUALITY

Step-by-step explanation:

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