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yan [13]
3 years ago
9

A right triangle has an area of 36 square units. If you draw scaled copies of this triangle using the scale factors in the table

, what will the areas of these scaled copies be? Please help me this is due 12:30
Mathematics
1 answer:
kolbaska11 [484]3 years ago
8 0
The answer that should be correct would be 5
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Five years ago, the tree you planted measured 4 meters 9 decimeters tall. Today that tree measures 6 meters, 1 decimeter. How mu
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Answer: 1.2metres

Step-by-step explanation:

Five years ago, tree was 4.9m

Today, tree is 6.1m

Subtract 4.9m from 6.1m

Tree has grown by 1.2m

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3 years ago
Triangle MNP is dilated according to the rule DO,1.5 (x,y)(1.5x, 1.5y) to create the image triangle M'N'P, which is not shown. W
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Step-by-step explanation:

7 0
3 years ago
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An atrium is being designed to house an exhibit of tropical birds. The atrium must enclose 250,000 cubic feet of space, and the
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The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium.

<h3>Can this atrium be built in the rectangular plot of land?</h3>

The atrium with the <em>maximum allowable</em> radius (<em>R</em>), in feet, is represented in the image attached. The <em>real</em> atrium is possible if and only if the <em>real</em> radius (<em>r</em>) is less than the maximum allowable radius and therefore, the <em>real</em> volume (<em>V</em>), in cubic feet, must be less than than <em>maximum possible</em> volume (<em>V'</em>), in cubic feet.

First, we calculate the volume occupied by the maximum allowable radius:

<em>V' =</em> (8 · π / 3) · (45 ft)³

<em>V' ≈</em> 763407.015 ft³

The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium. \blacksquare

To learn more on volumes, we kindly invite to check this verified question: brainly.com/question/13338592

3 0
2 years ago
Fraction that is smaller than -2^1^3
lapo4ka [179]
Isn't it 1/8?
I hope this helped i think i just simplified xD

7 0
3 years ago
How to do this problem because it's hard
Elenna [48]
You will need to set up and solve 2 equations:
A) 3 Vans + 10 Buses = 379
B) 14Vans + 13 Buses = 624
Multiply equation A by -14
A) -42 Vans -140 Buses = -5,306  then Multiply equation B by 3
B) 42 Vans + 39 Buses = 1,872
Adding BOTH equations
-101 Buses = -3,434
Each Bus holds 34 Students

Putting this into equation A
A) 3 Vans + 10 Buses = 379
A) 3 Vans + 10 * 34 = 379
A) 3 Vans +340 = 379
A) 3 Vans = 39
Each van = 13 students




4 0
3 years ago
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