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3 years ago

A football team loses a total of 12 yards in 4 plays. On average how many yards did the team move the ball per play?

Mathematics

1 answer:

HACTEHA [7]3 years ago

8 0

The team moved the ball -3 yards per play.

Step-by-step explanation:

Given,

Total yards lost = 12 yards

Total plays = 4 plays

As the yards are lost, therefore, we will use negative sign.

Yards per play = $\frac{Number\ of\ yards}{Number\ of\ plays}$

Yards per play = $\frac{-12}{4}$

Yards per play = -3

The team moved the ball -3 yards per play.

Keywords: division, unit rate

Learn more about division at:

#LearnwithBrainly

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Find m∠ABD and m∠CBD given m∠ABC = 111∘.

sineoko [7]

Answer:

m∠ABD = 88º

m∠CBD = 23º

Step-by-step explanation:

(-10x + 58) + (6x + 41) = 111

Combine like terms

-4x + 99 = 111

Subtract 99 from both sides

-4x = 12

Divide both sides by -4

x = -3

------------------------

m∠ABD = -10x + 58

m∠ABD = -10(-3) + 58

m∠ABD = = 30 + 58

m∠ABD = 88º

m∠CBD = 6x + 41

m∠CBD = 6(-3) + 41

m∠CBD = -18 + 41

m∠CBD = 23º

7 0

2 years ago

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A large mixing tank currently contains 350 gallons of water, into which 10 pounds of sugar have been mixed. A tap will open, pou

Marysya12 [62]

Answer

Let t be number of minutes since tap is opened

water is increased by 20 gallons of water per minute.

sugar increase rate of 3 pounds per minute

water :- W(t) = 350 + 10 t

sugar :- S(t) = 10 + 3 t

concentration

C(t) = $\dfrac{S(t)}{W(t)}$

at t = 15 minutes

C(15) = $\dfrac{S(15)}{W(15)}$

C(15) = $\dfrac{10 + 3\times 15 }{350 + 10\times 15}$

C(15) = 0.11

at beginning t = 0 minutes

C(0) = $\dfrac{S(0)}{W(0)}$

C(0) = $\dfrac{10 + 3\times 0}{350 + 10\times 0}$

C(0) = 0.0286

C(15) > C(0)

hence, concentration is increasing as time is passing.

3 0

3 years ago

Can you please help?

gogolik [260]

Answer:

sry i cant help you bcoz i havent read this type of exercise yet

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2 years ago

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If the composition of two functions is:

NARA [144]

9514 1404 393

Answer:

x ≠ 3

Step-by-step explanation:

In any case, the domain is restricted to values of the variable for which the function is defined. The value 1/0 is not defined, so the variable cannot allow the denominator to be zero. The denominator x-3 will be zero for x=3, so that value of the variable cannot be in the domain.

The domain is all real numbers except x=3.

_____

<em>Additional comments</em>

It is useful to become familiar with the domains of different functions. As we saw above, the reciprocal of 0 is undefined. The square root of a negative number is undefined. The log of a non-positive number is undefined. Trig functions are defined everywhere, but their inverse functions are not. Polynomial functions are defined everywhere, but ratios of polynomials have the same restriction on denominators that we see above.

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2 years ago

Need help with this

Artemon [7]

The answer is D (the last answer choice)

3 0

3 years ago