A circuit breaker is a switch that automatically opens a circuit if too much current flows through it.
1 answer:
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Explanation:
It is known that of propionic acid = 4.87
And, initial concentration of propionic acid =
= 0.158 M
Concentration of sodium propionate = \frac{0.26}{1.20}[/tex]
= 0.216 M
Now, in the given situation only propionic acid and sodium propionate are present .
Hence, pH =
=
= 4.87 + log (1.36)
= 5.00
- Therefore, when 0.02 mol NaOH is added then,
Moles of propionic acid = 0.19 - 0.02
= 0.17 mol
Hence, concentration of propionic acid =
= 0.14 M
and, moles of sodium propionic acid = (0.26 + 0.02) mol
= 0.28 mol
Hence, concentration of sodium propionic acid will be calculated as follows.
= 0.23 M
Therefore, calculate the pH upon addition of 0.02 mol of NaOH as follows.
pH =
=
= 4.87 + log (1.64)
= 5.08
Hence, the pH of the buffer after the addition of 0.02 mol of NaOH is 5.08.
- Therefore, when 0.02 mol HI is added then,
Moles of propionic acid = 0.19 + 0.02
= 0.21 mol
Hence, concentration of propionic acid =
= 0.175 M
and, moles of sodium propionic acid = (0.26 - 0.02) mol
= 0.24 mol
Hence, concentration of sodium propionic acid will be calculated as follows.
= 0.2 M
Therefore, calculate pH upon addition of 0.02 mol of HI as follows.
pH =
=
= 4.87 + log (0.114)
= 4.98
Hence, the pH of the buffer after the addition of 0.02 mol of HI is 4.98.
<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.
<u>Explanation:</u>
All radioactive decay processes undergoes first order reaction.
To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:
where,
k = rate constant = ?
t = time taken = 1.52 hrs
= Initial concentration of reactant = 100 g
[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g
Putting values in above equation, we get:
To calculate the half life period of first order reaction, we use the equation:
where,
= half life period of first order reaction = ?
k = rate constant =
Putting values in above equation, we get:
Hence, the half life of the sample of silver-112 is 3.303 hours.
Answer:
0.7 moles of Chlorine gas is required.
Explanation:
The reaction is balanced as follows:
2Na + ------> 2NaCl
According to stoichiometry,
2 mole Sodium reacts with 1 mole Chlorine gas
∴1 mole Sodium reacts with 1/2 moles of Chlorine gas
∴1.4 mole sodium reacts with 1.4/2 moles of Chlorine gas
= 0.7 moles of Chlorine gas
So, 0.7 moles of Chlorine gas is required.