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andreev551 [17]
3 years ago
14

Why is potasium oxide not used to investigate property of hydrogen gas​

Chemistry
1 answer:
Anarel [89]3 years ago
3 0

Because potassium is more reactive than hydrogen

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Naftalin buharlaşırsa hangi olay gerçekleşir?<br><br>ACİLLLLLL!​
Eduardwww [97]

Answer:

Turkish: Bir gaza dönüşecekler ve gaz, güveler ve güve larvaları için çok zehirlidir.

English:They will turn in to a gass and the gass is very toxic to moths and moth larvae.

6 0
2 years ago
Consider the reaction between iron (III) oxide, Fe2O3 and carbon monoxide, CO. Fe2O3 + 3CO --&gt; 2Fe + 3CO2 In the process, 213
s344n2d4d5 [400]
To calculate the mass of Fe formed in a) we get first the limiting reactant between Fe2O3 and CO. Given the masses, the ratio of Fe2O3 is 1.33 while that of CO is 1.67. Hence the limiting reagent is Fe2O3. The mass of Fe formed is 148.98 grams. In b, the needed CO is only 112.04 grams. Hence, the excess is 27. 96 grams. 
8 0
3 years ago
If the H+ in a solution is 1x10^-1 mol/L what is the OH-
damaskus [11]
PH scale is used to determine how acidic or basic a solution is.
we have been given the hydrogen ion concentration. Using this we can calculate pH,
pH = - log[H⁺]
pH = - log (1 x 10⁻¹ M)
pH = 1
using pH can calculate pOH
pH + pOH = 14
pOH = 14 - 1
pOH = 13
using pOH we can calculate the hydroxide ion concentration 
pOH = - log [OH⁻] 
[OH⁻] = antilog(-pOH)
[OH⁻] = 10⁻¹³ M
hydroxide ion concentration is 10⁻¹³ M
8 0
3 years ago
How much heat is lost when 1277 g of H20 at 400 K is changed into ice at 263 K? Plz help I’ll give you brainliest 20 points
OLga [1]

The heat lost is -7.32*10^-^5J

The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.

<h3>Heat Transfer</h3>

This is the heat transferred from a body of higher temperature to a body of lower temperature.

Q = mc(\delta)T

  • Q = Heat Transfer
  • m = mass = 1277g
  • ΔT  = change in temperature

\delta T = (400 - 273) - (263 - 273) = \\&#10;\delta T = T_2 - T_1\\&#10;\delta T = -10 - 127\\&#10;\delta T = -137^0C

We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.

Solving for heat transfer

Q = mc\delta T\\&#10;Q = 1277 * 4.186 * -137\\&#10;Q = -732336.514J

The heat loss is approximately -7.32*10^-^5J

Learn more on heat transfer here;

brainly.com/question/16055406

6 0
2 years ago
Explain how the Law of Conservation of Mass is demonstrated In photosynthesis and cellular Respiration chemical equations. (Less
Oksi-84 [34.3K]

Explanation:

  • According to the law of conservation of mass, In a chemical reaction, mass is neither created nor destroyed. In other words, the total mass for the reactants needs to equal the total mass of the products.
  • <u><em>In photosynthesis the reactants are 6 carbon dioxide, 6 water and sunlight. The mass of these reactants adds to equal the mass of the products, which are 1 glucose and 6 oxygen. </em></u>
  • <u><em>Cellular respiration on the other hand uses glucose and oxygen gas to produce water, carbon dioxide, and a usable form of energy known as ATP.</em></u>
  • Cellular respiration is the opposite of photosynthesis, such that the products of photosynthesis are the reactants of cellular respiration. Cellular respiration also obeys the law of conservation of mass.
6 0
3 years ago
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