Question

Rohan did a survey in four bird parks and wrote the following observations:

Answer 1

Answer:  Park P

Step-by-step explanation:

Since, According to the question,

Number of yellow bird in park P = 33

Total number of the bird in park P = 53

Thus, the percentage of yellow bird in park P = $\frac{33}{53} \times 100$= 62.264150943% ≈ 62 %

Number of yellow bird in park Q = 20

Total number of the bird in park Q = 48

Thus, the percentage of yellow bird in park P = $\frac{20}{48} \times 100$=41.666666666% ≈ 42%

Number of yellow bird in park R = 54

Total number of the bird in park R = 90

Thus, the percentage of yellow bird in park R = $\frac{54}{90} \times 100$= 60 %

Number of yellow bird in park S = 44

Total number of the bird in park S = 83

Thus, the percentage of yellow bird in park P = $\frac{44}{83} \times 100$=53.012048192 % ≈ 53 %

Since, 62% > 60% > 53% > 42%

Therefore, highest percentage of the yellow bird is 62 %

Which is present in park P.