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Andre45 [30]
2 years ago
5

Rohan did a survey in four bird parks and wrote the following observations:

Mathematics
1 answer:
stiks02 [169]2 years ago
8 0

Answer:  Park P

Step-by-step explanation:

Since, According to the question,

Number of yellow bird in park P = 33

Total number of the bird in park P = 53

Thus, the percentage of yellow bird in park P = \frac{33}{53} \times 100= 62.264150943% ≈ 62 %

Number of yellow bird in park Q = 20

Total number of the bird in park Q = 48

Thus, the percentage of yellow bird in park P = \frac{20}{48} \times 100=41.666666666% ≈ 42%

Number of yellow bird in park R = 54

Total number of the bird in park R = 90

Thus, the percentage of yellow bird in park R = \frac{54}{90} \times 100= 60 %

Number of yellow bird in park S = 44

Total number of the bird in park S = 83

Thus, the percentage of yellow bird in park P = \frac{44}{83} \times 100=53.012048192 % ≈ 53 %

Since, 62% > 60% > 53% > 42%

Therefore, highest percentage of the yellow bird is 62 %

Which is present in park P.

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Which of the following is the graph of the quadratic function y - x? +10x+16 ?
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Find the x and y intercepts:

Factor y = x^2+10x + 16 to find the x intercepts

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Solve with interval notation Solve: 5 | x − 2 | + 4 > 8
Gnesinka [82]

Answer:

x<6/5, x>14/5

Step-by-step explanation:

Steps

$5\left|x-2\right|+4>8$

$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$

$5\left|x-2\right|+4-4>8-4$

$\mathrm{Simplify}$

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$\mathrm{Divide\:both\:sides\:by\:}5$

$\frac{5\left|x-2\right|}{5}>\frac{4}{5}$

$\mathrm{Simplify}$

$\left|x-2\right|>\frac{4}{5}$

$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$

$x-2<-\frac{4}{5}\quad\mathrm{or}\quad\:x-2>\frac{4}{5}$

Show Steps

$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$

Show Steps

$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$

$\mathrm{Combine\:the\:intervals}$

$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$

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3 years ago
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Answer:

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Step-by-step explanation:

The description of the garden fits that of 3 squares arranged side-by-side. The area of each of those would be 100 ft², so their side length would be ...

  s = √A= √(100 ft²) = 10 ft

This dimension is the width of the garden, whose length is 3 times this amount.

The length and width of the garden are 30 ft and 10 ft, respectively.

3 0
3 years ago
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