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laila [671]
3 years ago
13

Pasion wants to rent a car to take a trip and has a budget of $75. There is a fixed rental fee of $25 and a daily fee of $10. Wr

ite an inequality that would be used to solve for the maximum number of days for which Pasion can rent the car on her budget.
Mathematics
2 answers:
defon3 years ago
5 0

Answer:

The maximum number of days is 5

Step-by-step explanation:

Let

x ----> the number of days

y ---> the total cost to rent a car in dollars

we know that

The fixed rental fee plus the daily fee multiplied by the number of days must be less than or equal to Pasion's budget

so

The inequality that represent this situation is

25+10x\leq 75

Solve the inequality  for x    

Subtract 25 both sides      

10x\leq 75-25                  

10x\leq 50        

Divide by 10 both sides          

x\leq 5\ days

therefore

The maximum number of days is 5

Schach [20]3 years ago
3 0

Answer:

25 + 10x ≤ 75

Step-by-step explanation:

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Answer:

7/24

Step-by-step explanation:

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3 years ago
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The distance between New York City, NY, and Louisville, KY is 720 miles. One morning a train traveling 80 mph left from New York
beks73 [17]

Answer:

2 hours

Step-by-step explanation:

Given : The distance between New York City, NY, and Louisville, KY is 720 miles. One morning a train traveling 80 mph left from New York. Two hours later a slower train, traveling at 60 mph, left Louisville.

To find : How many hours will the slower train travel for before both trains will arrive at the same point?

Solution : Let the distance covered by NY is x

and  let the distance covered by KY is y

Total distance covered is  x+y=720   ........[1]

→ New York city,

Distance traveled = x

Speed of the train = 80 mph

Time taken = t+2

Formula is \text{Time}=\frac{\text{Distance}}{\text{Speed}}

t+2=\frac{x}{80} .......[2]

→ Louisville,

Distance traveled = y

Speed of the train = 60 mph

Time taken = t

Formula is \text{Time}=\frac{\text{Distance}}{\text{Speed}}

t=\frac{y}{60} .......[3]

Put the value of t from [3] into [2]

\frac{x}{80}- \frac{y}{60}=2  ......[4]

Now, we solve equation [1] and [4],

Put the value of y from [1] and put back in [4], y=720-x

\frac{x}{80}- \frac{y}{60}=2

\frac{x}{80}- \frac{720-x}{60}=2

\frac{60x-80(720-x)}{80\times60}=2

60x-57600+80x=9600

140x-57600=9600

140x=57600+9600=67200

x=\frac{67200}{140}=480

Put x=480 in [1]

x+y=720  

480+y=720  

y=240  

So, The distance covered by train from New York city is x=480 miles

The distance covered by train from Louisville is y=240 miles.

Now put value of y in [3] to get time,

t=\frac{y}{60}

t=\frac{240}{60}

t=4

So, The time taken by train from Louisville is 4 hr.

The time taken by train from New York city is t+2=4+2=6 hr.

→ 6-4=2 hours will the slower train travel for before both trains will arrive at the same point.




7 0
3 years ago
Please help me solve this priblem
Over [174]
It would be c. 12 inches

H = V/lw

The Length * Width = 450
and the volume is 5400
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