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Lady bird [3.3K]
3 years ago
9

Please save the program with the name ‘triangle.c’

Computers and Technology
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

1. #include <stdio.h>

2. int main()

3. {

4.     int k;

5.     int j;

6.     int i;

7.     int array[7];

8.     array[0] = 1;

9.     for (i = 1; i < 9; ++i)

10.     {

11.        array[i] = array[i-1]*2;

12.        for (j=0; j < i; ++j)

13.        {

14.          printf("%d ",array[j]);

15.        }      

16.        for (k=i-2; k > -1; --k)

17.        {

18.          printf("%d ", array[k]);  

19.        }

20.        printf("\n");      

21.     }  

22.     return 0;

23. }

Explanation:

  • From line 1 to 3 we start the main function
  • From line 4 to 7 we declare the variables that we are going to be using throughout the program including an array of 7 positions
  • On line 8 we initialize the array with one to match the sequence
  • From line 9 to 10 we create a for loop to create the 9 sequences of numbers
  • On line 11 we assign values to the array by taking the previous value and multiplying it by 2, this way we can create the sequence 1,2,4,8,32...
  • From line 12 to 15 we print the ordered array
  • From line 16 to 19 we print the inverse array minus one  
  • On line 20 we print an enter

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Answer:

sed '/march/{d;}' birthdays.txt > result .txt

Explanation:

sed syntax is basically:

<em>sed '/expression/{command;command;...;}' inputfile > outputfile</em>

  • First, for the expression part, we use /march/ to match all lines containing that string.
  • Then for the command part, we only use {d} command to delete every matching line found.
  • The third part contains the input file to process, I have named it birthdays.txt, but it could have been any other file needed.
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Create a Python program in a file named loops1.py that does the following: a. Use a while loop to keep asking the user for input
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Answer:

mystr = input("Enter a string ")

length = len(mystr)

while length<10:

   mystr = input("Enter a string ")

   length = len(mystr)

   if(length>=10):

       break

if len(mystr)%2==0:

   print(mystr.lower())

else:

   print(mystr.upper())

Explanation:

The variable mystr is used to save user's input which is received with the input function

A second variable length is used to save the length of the input string Using a while statement the user is continually prompted to enter a string while length is less than 10.

If length is greater or equal to 10. We check for even or odd using the modulo (%) operator.

We use lower() and upper() to change the case of the string

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Answer:

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Step 1: Start

Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

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Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

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Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

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Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

<em>Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n) </em>

Download txt
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