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3 years ago

Please save the program with the name ‘triangle.c’

Computers and Technology

1 answer:

konstantin123 [22]3 years ago

7 0

Answer:

1. #include <stdio.h>

2. int main()

3. {

4. int k;

5. int j;

6. int i;

7. int array[7];

8. array[0] = 1;

9. for (i = 1; i < 9; ++i)

10. {

11. array[i] = array[i-1]*2;

12. for (j=0; j < i; ++j)

13. {

14. printf("%d ",array[j]);

15. }

16. for (k=i-2; k > -1; --k)

17. {

18. printf("%d ", array[k]);

19. }

20. printf("\n");

21. }

22. return 0;

23. }

Explanation:

From line 1 to 3 we start the main function
From line 4 to 7 we declare the variables that we are going to be using throughout the program including an array of 7 positions
On line 8 we initialize the array with one to match the sequence
From line 9 to 10 we create a for loop to create the 9 sequences of numbers
On line 11 we assign values to the array by taking the previous value and multiplying it by 2, this way we can create the sequence 1,2,4,8,32...
From line 12 to 15 we print the ordered array
From line 16 to 19 we print the inverse array minus one
On line 20 we print an enter

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Write a sed command that will display all lines of the birthday file that do not contain the string March. What was the sed comm

Dmitriy789 [7]

Answer:

sed '/march/{d;}' birthdays.txt > result .txt

Explanation:

sed syntax is basically:

<em>sed '/expression/{command;command;...;}' inputfile > outputfile</em>

First, for the expression part, we use /march/ to match all lines containing that string.
Then for the command part, we only use {d} command to delete every matching line found.
The third part contains the input file to process, I have named it birthdays.txt, but it could have been any other file needed.
Finally "> result .txt" makes the script output to be saved into a file named result.txt

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2 years ago

Create a Python program in a file named loops1.py that does the following: a. Use a while loop to keep asking the user for input

Rashid [163]

Answer:

mystr = input("Enter a string ")

length = len(mystr)

while length<10:

mystr = input("Enter a string ")

length = len(mystr)

if(length>=10):

break

if len(mystr)%2==0:

print(mystr.lower())

else:

print(mystr.upper())

Explanation:

The variable mystr is used to save user's input which is received with the input function

A second variable length is used to save the length of the input string Using a while statement the user is continually prompted to enter a string while length is less than 10.

If length is greater or equal to 10. We check for even or odd using the modulo (%) operator.

We use lower() and upper() to change the case of the string

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3 years ago

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What year did polaroid introduce one-step photography with the SX-70

blagie [28]

Answer:

I first saw the Polaroid SX-70—the one-step instant camera introduced in 1972 by the company's co-founder, Dr.

Explanation:

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2 years ago

You are a visitor at a political convention with delegates; each delegate is a member of exactly one political party. It is impo

Fed [463]

Answer:

The algorithm is as follows:

Step 1: Start

Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

Step 7: Else

Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

The next person on the list is set to index 1

Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

Step 6.1: If Parties[Individual] == Parties[I]:

Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

<em>Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n) </em>

Download txt

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Answer:

number 4

Explanation:

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3 years ago

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