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3 years ago

15

HELP ASAP!!!

1 answer:

givi [52]3 years ago

4 0

This law states that, despite chemical reactions or physical transformations, mass is conserved — that is, it cannot be created or destroyed — within an isolated system. In other words, in a chemical reaction, the mass of the products will always be equal to the mass of the reactants.

I looked this up but hope it helps!

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The surface temperature on Venus may approach 757 K. What is this temperature in degrees Celsius?

kotykmax [81]

Explanation:

1 ) Temperature of Venus in Kelvins = 757 Kelvins

$0^oC=273 Kelvins$

Temperature of Venus in degrees Celsius = $757-273 K=484 K$

2 ) Temperature on Mercury at night = $-269^oF$

$(T)^oC=((T)^oF-32)\times \frac{5}{9}$

$(T)^oC=((-269)^oF-32)\times \frac{5}{9}=167.22^oC$

Temperature on Mercury at night in degree Celsius = 167.22° C

7 0

3 years ago

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What is the highest occupied energy level for an atom of copper (Cu)? *

bonufazy [111]

Answer:

third energy level - 18

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8 0

3 years ago

5. Which particle can not be accelerated by the electric

Sauron [17]

Answer:

A. neutron

Explanation:

Neutrons cannot be accelerated in an electric or magnetic field because they are neutral in charge.

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3 years ago

Write formulas and names for two binary molecular compounds

lyudmila [28]

Answer:

NaCl sodium chloride

HF hydrogen flouride

Explanation:

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3 years ago

A compound that is composed of only carbon and hydrogen contains 80.0% c and 20.0% h by mass. What is the empirical formula of t

gladu [14]

<u>Solution</u> : Emperical Formula = $CH_{3}$

Emperical Formula - A formula that gives the simplest whole number ratio of atom in a compound.

In the question percentages are given then assume that the total mass is 100grams so that the mass of each element is equal to the percentage given.

Given : 80.0g Carbon

20.0g Hydrogen

First convert the given masses into moles.

$80.0g\text{ C} \times \frac{1 g/mole \text{ C}}{12.0 g/mole \text{ C}}= 6.66\text{mole of C}$

$20.0g\text{ H} \times \frac{1 g/mole \text{ H}}{1 g/mole \text{ H}}= 20.0\text{mole of H}$

Value of each mole divided by the smallest number of moles and then round off.

Moles ratio of the element are

$\frac{6.66}{6.66}\text{mole of C}= 1$

$\frac{20.0}{6.66}\text{mole of C}= 3$

This is the mole ratio of the elements and is repersented by the subscript in the emperical formula.

Emperical Formula = $CH_{3}$

3 0

4 years ago