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Degger [83]
2 years ago
6

How many moles of copper are present in a sample that contains 4.55 x 10^24 atoms of copper

Chemistry
1 answer:
FinnZ [79.3K]2 years ago
3 0

Hope you could understand.

If you have any query, feel free to ask.

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The side chains of amino acids may contain..
salantis [7]

The correct answer is d)all of above

examples for a are tyrosine for b lysine and for c isoleucine

6 0
3 years ago
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3. What is the formula for the compound formed from the magnesium ion and nitrate?
bija089 [108]

Answer:

D.) Mg(NO₃)₂

Explanation:

Since magnesium (Mg) is a metal and nitrate (NO₃) is a polyatomic anion, they would combine to form an ionic compound. Magnesium would form the cation Mg²⁺ because it generally has 2 valence electrons. Nitrate always has a -1 charge.

In order for the overall compound to be neutral (have a charge of 0), there must be one Mg²⁺ and two NO₃⁻ ions in the compound (+2 + (-1) + (-1) = 0).

Therefore, the formula for the compound formed is Mg(NO₃)₂.

8 0
1 year ago
After a big game, you put your water bottle inside the refrigerator. The next
12345 [234]

Mostly and for what I would say is A

6 0
2 years ago
Why does every plant cell have a nucleus
Lena [83]
Every plant cell has a nucleus because a nucleus controls the cell's main <span>activities.</span>
3 0
2 years ago
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Free-energy change, ΔG∘, is related to cell potential, E∘, by the equation ΔG∘=−nFE∘ where n is the number of moles of electrons
elena-s [515]

Answer:

-372000 J or -372 KJ

Explanation:

We have the electrochemical reaction as;

Mg(s)  +  Fe^2+(aq)→  Mg^2+(aq)  +   Fe(s)

We must first calculate the E∘cell from;

E∘cathode -  E∘anode

E∘cathode = -0.44 V

E∘anode = -2.37 V

Hence;

E∘cell = -0.44 V -(-2.37 V)

E∘cell = 1.93 V

n= 2 since two electrons were transferred

F=96,500C/(mol e−)

ΔG∘=−nFE∘

ΔG∘= -( 2 * 96,500 * 1.93)

ΔG∘= -372000 J or -372 KJ

4 0
2 years ago
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