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shtirl [24]
4 years ago
11

A chemist is analyzing a substance known to be an Arrhenius acid. Which of the following substances could it be?

Chemistry
1 answer:
Stels [109]4 years ago
8 0

Answer:

HNO3

Explanation:

Nitric Acid is an example of an Arrhenius acid.

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60 kg of fuel was completely burnt for an experiment. The amount of heat energy was found to be 180000KJ. Calculate calorific va
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Answer:

3000 kJ/kg

Explanation:

The calorific value of a substance is the amount of heat produced per unit mass by the combustion of the substance.

It is given by:

C=\frac{Q}{m}

where

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m is the mass of the fuel

In this problem, we have:

m = 60 kg is the mass of fuel

Q=180,000 kJ is the amount of heat released

Therefore, the calorific value of the fuel is:

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6 0
3 years ago
A chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms,
alina1380 [7]

Answer:

it forms :

1. Gold ( Au )

2. Zinc nitrate ( Zn(NO3)2 )

Explanation:

When a chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms Gold and Zinc nitrate .

it's a single displacement reaction,

here's the balanced equation for above reaction :

3 Zn + 2 Au(NO3)3 =》3 Zn(NO3)2 + 2 Au

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