1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GenaCL600 [577]
3 years ago
11

When calcium is allowed to react with nitrogen, calcium nitride is formed. If 24.0 g of calcium and 12.0 g of nitrogen are avail

able for this reaction, the limiting reagent will be?
Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
8 0
What are the mol ratios? if you’re just comparing with the mass (which i doubt so since most limiting questions require u to compare the mols)

but if u are, the limiting would be nitrogen since it’s lesser than calcium mass
You might be interested in
Who is the father of chemistry ​
Xelga [282]

Answer: Antoine Lavoisier

3 0
3 years ago
Read 2 more answers
2.122 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium bicarbonate (FW = 100.1154 g/
aleksandr82 [10.1K]

Answer:

The weight percent of potassium carbonate is 50,8 wt% and of potassium bicarbonate 49,2 wt%

Explanation:

The reactions of potassium carbonate (K₂CO₃) and potassium bicarbonate (KHCO₃) with HCl produce:

K₂CO₃ + 2HCl → 2KCl + CO₂ + H₂O

KHCO₃ + HCl → KCl + CO₂ + H₂O

That means that you need 2 moles of HCl to titrate potassium carbonate and 1 mol to titrate potassium bicarbonate.

The moles of HCl to titrate the mixture are:

0,03416L×\frac{0,762mol}{1L} = <em>0,02603 mol of HCl</em>

If X is mass of K₂CO₃ and Y is mass of KHCO₃ in the mixture, the moles of HCl to titrate the mixture are equals to:

0,02603 mol = 2X×\frac{138,2058 g}{1mol} + Y×\frac{100,1154 g}{1mol} <em>(1)</em>

As the mass of the mixture is 2,122g:

2,122g = X + Y <em>(2)</em>

Replacing (2) in (1):

0,02603 mol = 0,01447 (2,122-Y) + 9,988x10⁻³Y

0,02603 mol = 0,0307 - 0,01447Y + 9,988x10⁻³Y

-4,6778x10⁻³ = -4,4827x10⁻³Y

1,044g = Y <em>-mass of potassium bicarbonate-</em>

Thus:

X = 1,078g <em>-mass of potassium carbonate-</em>

The weight percent of potassium carbonate is:

\frac{1,078g}{2,122g}×100 =<em> 50,8 wt%</em>

The weight percent of potassium bicarbonate is:

\frac{1,044g}{2,122g}×100 = <em>49,2 wt%</em>

<em></em>

I hope it helps!

5 0
3 years ago
Suppose you had an organic molecule such as cystine, and you chemically removed the --nh2 group and replaced it with --cooh. Dra
Serggg [28]

Cystine is dimer of Cystein amino acid formed by oxidation reaction. Its main function is to provide mechanical strength to proteins and allow them to retain their 3-D structures and also serves as a substrate for the cystine-glutamate antiporter.

As shown in figure cystine has two amino groups (highlighted blue) and two carboxylic groups (highlighted green). In its original structure cystine is neutral in nature as it has equal number of basic (NH₂) and acidic (COOH) moieties along with two chiral centers (asymmetric carbons) highlighted with red spots.

When one -NH₂ group is replaced by -COOH group the cystine is converted into an acidic compound with three COOH groups and a NH₂ group. Also, one asymmetric carbon will convert into a symmetrical carbon with a loss of one chiral carbon.

In second step, when another NH₂ is replaced by COOH, the acidic strength of resulting compound will increase along with conversion of last chiral carbon into symmetric carbon.

Therefore, the final structure will be acidic in nature with zero chiral carbons as shown in figure attached below.

6 0
3 years ago
A volume of 40.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2
Anni [7]

<u>Answer:</u> The concentration of KOH solution is 1.215 M

<u>Explanation:</u>

For the given chemical equation:

2KOH(aq.)+H_2SO_4(aq.)\rightarrow K_2SO_4(aq.)+2H_2O(l)

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\\M_1=1.50M\\V_1=16.2mL\\n_2=1\\M_2=?M\\V_2=40.0mL

Putting values in above equation, we get:

2\times 1.50\times 16.2=1\times M_2\times 40.0\\\\M_2=\frac{2\times 1.50\times 16.2}{1\times 40.00}=1.215M

Hence, the concentration of KOH solution is 1.215 M

3 0
3 years ago
If the highest point on this landform is 650 feet and the lowest point is 0 feet, what is the relief of this landform?
STALIN [3.7K]
I just want to go to sleep but the answer is 15038282
4 0
3 years ago
Other questions:
  • Which ion is not an oxyanion? NO− SO4 2− CN− CO3 2−
    7·1 answer
  • What is the total amount of heat required to completely melt 347 grams of ice at this melting point
    5·1 answer
  • Which one of the following solutions will have the greatest concentration of hydroxide ions?
    11·1 answer
  • How are energy and work related? A. Energy is the force needed to do work B. Work times energy is force C. Energy is the capacit
    11·2 answers
  • Methane and ethane are both made up of carbon and hydrogen. In methane, there are 12.0 g of carbon for every 4.00 g of hydrogen,
    7·1 answer
  • numbers represented by the following prefi xes: (a) mega-, (b) kilo-, (c) deci-, (d) centi-, (e) milli-, (f) micro-, (g) nano-,
    15·1 answer
  • Which method of heat transfer can take place without matter? O Conduction O Convection O Insulation O Radiation​
    15·2 answers
  • Q2.
    6·1 answer
  • Https://ny.pbslearningmedia.org/resource/chemical-engineering-your-future/chemical-engineering-video/
    8·1 answer
  • for the following reaction: 1 CuO + 1 H2 --&gt; 1 Cu +1H2O, what is the quantity of moles of H2O when there are 240 grams of CuO
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!