Answer:
The specific heat of copper is 0.37 J/g°C
Explanation:
<u>Step 1: </u>Data given
Mass of copper = 19.5 grams
Initial temperature of copper = 98.27 °C
Mass of water = 76.3 grams
Initial temperature of water = 24.05 °C
Final temperature of water and copper = 25.69 °C
<u>Step 2:</u> Calculate specific heat of copper
Qgained = -Qlost
Q = m*c*ΔT
Qwater = -Qcopper
m(water) * c(water) * ΔT(water) = - m(copper) * c(copper) *ΔT(copper)
⇒ with m(water) = 76.3 grams
⇒ with c(water) = 4.184 J/g°C
⇒ with ΔT(water) = T2-T1 = 25.69 - 24.05 = 1.64
⇒ with m(copper) = 19.5 grams
⇒ with c(copper) = TO BE DETERMINED
⇒ with ΔT(copper) = T2-T1 = 25.69 - 98.27 = -72.58
76.3 * 4.184 * 1.64 = - 19.5 * c(copper) * -72.58
523.552 = 1415.31 * c(copper)
c(copper) = 0.37 J/g°C
The specific heat of copper is 0.37 J/g°C
