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fredd [130]
4 years ago
6

How many quarters are in $500

Chemistry
1 answer:
Alexandra [31]4 years ago
8 0

Answer:

\boxed{2000}

Explanation:

\text{4 quarters = \$1}\\\\\text{No. of quarters} = \text{\$500} \times \dfrac{\text{4 quarters}}{\text{\$1}} = \boxed{\textbf{2000 quarters}}

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who else has found that something they did or readed or whatever it is they had completely forgot about and just remembered abou
Dominik [7]

Answer:

Yes I do this a lot :)

Explanation:

6 0
3 years ago
A balloon is filled with air. It has a volume of 720 mL at a temperature of 22°C. You put
liubo4ka [24]

Charles's Law.

<u>V1</u><u> </u> = <u>V2</u>

T1 T2

V1 = 720 mL

T1 = 22°C

T2 = 106°C

V2 = ?

then,

<u>7</u><u>2</u><u>0</u><u> </u> = <u>V2</u><u> </u>

22 106

V2 = 3469 mL

5 0
2 years ago
You perform recrystallization of 1 g of impure acetanilide from water. The solubility of pure acetanilide in hot water is 55g/L.
likoan [24]

Answer:

38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.

Explanation:

Mass of acetanilide to be dissolved in hot water = 2.1 g

Mass of hot water to be used = m

Solubility of acetanilide = 55 g/L

This means that 55 grams of acetanilide dissolves in 1 L of hot water.

Then 1 grams of acetanilide will dissolve in :

\frac{1}{55}\times 2.1 L=0.0382 L

0.0382 L = 0.0382 × 1000 mL =38.2 mL

1 L = 1000 mL

38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.

8 0
3 years ago
If I have 5.275 moles of gas at a temperature of 575 K and a pressure of 7.75 atmospheres, what is the volume of the gas?
elena55 [62]

Answer:

hi

Explanation:

4 0
3 years ago
Calculate the volume in milliliters of a 2.09 M silver nitrate solution that contains 400 g of silver nitrate AgNO3. Round your
Liula [17]

<u>Answer:</u> The volume of solution is 1.13 L

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

We are given:

Molarity of solution = 2.09 M

Given mass of silver nitrate = 400. g

Molar mass of silver nitrate = 170 g/mol

Putting values in above equation, we get:

2.09M=\frac{400}{170\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{400}{170\times 2.09}=1.13L

Hence, the volume of solution is 1.13 L

4 0
3 years ago
Read 2 more answers
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