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3 years ago

Solve the following literal equations for the specified variable U+ka=ba,for a

Mathematics

1 answer:

Ad libitum [116K]3 years ago

7 0

The answer would be a=u divided by b-k

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Trevor and Marissa sell T-shirts at the craft fair Marisa has six fewer T-shirts then Trevor and together they have a total of 2

avanturin [10]

M + t = 26
m = t - 6

t - 6 + t = 26
2t - 6 = 26
2t = 26 + 6
2t = 32
t = 32/2
t = 16 <== Trevor has 16

m = t - 6
m = 16 - 6
m = 10...and Marissa has 10

3 0

3 years ago

Find the length of the third side. If necessary, write in simplest radical form.

pychu [463]

Answer: 84 is your answer hope this helped

plz make brainly

Step-by-step explanation:

6 0

3 years ago

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The ratio of collectible coins Juanita owns to coins that Elia owns is 3:1. Elia has 32 coins. How will the ratio of Juanita’s c

yaroslaw [1]

Hi there Maebe, since the ratio is 3:1 your answer is 96.

The ratio 3:1 is just saying Juanita has 3 times whatever Elita has. So, Elita’s 32 times 3 equals 96. :) I hope I’ve helped you. Please give me feedback if you need more help understanding!

7 0

3 years ago

You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the

il63 [147K]

Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that $n = 2809, \pi = \frac{1634}{2809} = 0.5817$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034$

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

6 0

3 years ago

Hello can you please help me posted picture of question

irina [24]

We are to form the combination of 6 objects taken 2 at a time. This can be expressed as 6C2

$6C2= \frac{6!}{2!*4!} \\ \\ 
= \frac{6*5}{2} \\ \\ 
=15$

This means, there can be 15 different combinations of 2 members that can sit in the front row.

So, the answer to this question is option A

6 0

3 years ago

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