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kvv77 [185]
3 years ago
9

A museum groundskeepers is creating a semicircle statuary garden with a diameter of 30 feet. The fencing cost 9.25 per linear fo

ot. About how much will the fencing cost altogether?
Mathematics
1 answer:
malfutka [58]3 years ago
5 0
It is equal to 277.5 

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Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. c2+3c
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(c+3/2)^2

Step-by-step explanation:

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The ratio of pink marbles to white marbles is 1:5 what percent of bag is pink marbles
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3 years ago
Listed below are the numbers of heroic firefighters who lost their lives in the United States each year while fighting forest fi
Marysya12 [62]

Answer:

Step-by-step explanation:

Hello!

Data

Year/Firefighters

2000: 20

2001: 18

2002: 23

2003: 30

2004: 20

2005: 12

2006: 24

2007: 9

2008: 25

2009: 15

2010: 8

2011: 11

2012: 15

2013: 34

<u>Common measures of variation</u>

<u>Variance</u>

S²= \frac{1}{n-1}[sumX^2-\frac{(sumX)^2}{n} ]

∑X= 20 + 18 + 23 + 30 + 20 + 12 + 24 + 9 + 25 + 15 + 8 + 11 + 15 + 34

∑X= 264

∑X²= 20² + 18² + 23² + 30² + 20² + 12² + 24² + 9² + 25² + 15² + 8² + 11² + 15² + 34²

∑X²= 5770

n= 14

S²= \frac{1}{13}[5770-\frac{(264)^2}{14} ]

S²= 60.90

<u>Standard deviation</u>

The standard deviation is the square root of the variance

S= √S²= √60.90= 7.80

<u>Coefficient of variation</u>

Is a relative standard deviation, it is defined as the division of the standard deviation (S) by the mean (X[bar)]. It has not units and is usually expressed in percentage. It shows the variability in relation to the mean.

C.V.= \frac{S}{X[bar]}*100 = \frac{7.80}{18.86}*100= 41.36%

The mean or average is a measurement of position and gives you an idea of the central value of the distribution of the data.

X[bar]= ∑X/n= 264/14= 18.86

<u>Range</u>

In the interval between the max and min values. It allows you to have an idea of the dispersion of the values.

R= Xmax - Xmin= 34 - 8= 26

Xmax= 34

Xmin= 8

<u>Inter Quartile Range</u>

Is the difference between Quantile 1 (C₁) and Quantile 3 (C₃). It shows the 50% mid values of the sample.

IQR= C₃ - C₁= 23.5 - 11.5 = 12

Quantile 1 (C₁) is the value that leaves 25% of the sample below and 75% of the sample above.

Pos1: n/4= 14/4= 3.5

The first quantile is the number between position 3 and position 4

8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34

C₁= (11+12)/2= 11.5

Quantile 3 (C₃) is the value that leaves 75% of the sample below and 25% of the sample above.

Pos3: n*3/4= 14*3/4= 10.5

The third Quantile is between position 10 and 11

8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34

C₃= (23+24)/2= 23.5

The measurements of variation don't allow you to know the origin of the data, that it is from consecutive years.

I hope it helps!

6 0
3 years ago
Can y’all help me with 7 - 12 showing work. Will be giving Brainliest:)) and for 13 and 14 I need help too :)) Help please :((((
Mekhanik [1.2K]
7= 16 lb >16 Oz 16x16=256
8= 1500 lb < 2T 2000+2000
9= 3T>5999 lb 2000x3
10= 1600 Oz > 10 lb 1600÷16=100
11= 19 lb>300 Oz 19x16=304oz
12= 8 oz= 1/2 lb 16 ounces = 1 pound 1/2=8
13= pounds=6000 tons= 1, 1.5
4 0
3 years ago
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