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3 years ago

9

A museum groundskeepers is creating a semicircle statuary garden with a diameter of 30 feet. The fencing cost 9.25 per linear fo

ot. About how much will the fencing cost altogether?

1 answer:

malfutka [58]3 years ago

5 0

It is equal to 277.5

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A family is building a circular fountain in the backyard. The yard is rectangular and measures 10x by 15x and the fountain is go

MrRa [10]

There is no answer for that or endless ur looking for the answer is 5x

7 0

3 years ago

!!!!please help!!! bed answer gets marked brainliest

Radda [10]

Answer:

(25 * 5.5) + (x * 2.9) + [(25 - x) * 4.4] = 50 * 4.5

Step-by-step explanation:

0.5 * 50Lbs. = 25 Lbs.

12.5 Lbs

12.5 Lbs.

4 0

2 years ago

Read 2 more answers

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

amm1812

Answer:

6546 students would need to be sampled.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.

This means that $n = 200, \pi = \frac{118}{200} = 0.59$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?

n students would need to be sampled, and n is found when M = 0.01. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.645\sqrt{\frac{0.59*0.41}{n}}$

$0.01\sqrt{n} = 1.645\sqrt{0.59*0.41}$

$\sqrt{n} = \frac{1.645\sqrt{0.59*0.41}}{0.01}$

$(\sqrt{n})^2 = (\frac{1.645\sqrt{0.59*0.41}}{0.01})^2$

$n = 6545.9$

Rounding up:

6546 students would need to be sampled.

3 0

3 years ago

Information about a play took up 1/3 of the pages in the program. Information about the actors took up 1/4 of the remaining page

Lisa [10]

Answer:

Step-by-step explanation:

Comment

Let the number of pages = x

Play = 1/3x

Actors = 1/4(x - 1/3 x)

Actors = 1/4(2/3x)

Actors = 2/12 x

Producer Director etc = 2 pages

Equation

Actors = 2 pages

2/12 x = 2

Solution

2x/12 = 2 Multiply both sides by 12

12*2x/12 = 2*12 Combine

2x = 24 Divide by 2

2x/2 = 24/2 Combine

x = 12

Answer

The program had 12 pages.

5 0

2 years ago

Tim buys a torch and battery the torch costs 11 times as much as the battery Tim pays with a ?10 note and he gets ?4.84 change h

KengaRu [80]

The cost of 1 battery is 0.43

Step-by-step explanation:

Let the cost of 1 battery be x

We are given that the torch costs 11 times as much as the battery

Cost of torch = 11x

Total cost of 1 battery and torch = 11x+x=12x

Tim pays $10

He receives change of $4.84

Total cost of 1 torch and battery = 10 - 4.84 =$5.16

So, $12x= 5.16$

$x= \frac{5.16}{12}$

$x=0.43$

Hence the cost of 1 battery is 0.43

6 0

3 years ago