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tester [92]
3 years ago
8

Find the x- and y-intercept x + 4y = 36

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
6 0

Answer:

x= 36 and y= 9

Step-by-step explanation:

because I said so. jk math

malfutka [58]3 years ago
3 0

Answer:

x-intercept: 36

y-intercept: 9

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • The x-intercept occurs when y=0
  • The y-intercept occurs when x=0

<u>1) Determine the x-intercept</u>

x + 4y = 36

Plug in 0 for y

x + 4(0) = 36\\x=36

Therefore, the x-intercept is 36.

<u>2) Determine the y-intercept</u>

x + 4y = 36

Plug in 0 for x

0 + 4y = 36\\4y = 36

Divide both sides by 4

y=9

Therefore, the y-intercept is 9.

I hope this helps!

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nevsk [136]
I'm assuming you're talking about the indefinite integral

\displaystyle\int e^{-x^2/2}\,\mathrm dx

and that your question is whether the substitution u=\dfrac x{\sqrt2} would work. Well, let's check it out:

u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}
\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du
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which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried u=\sqrt t next? Then \mathrm du=\dfrac{\mathrm dt}{2\sqrt t}, giving

=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, taking the derivative of both sides yields

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

and so the antiderivative would be

\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.
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Sunny_sXe [5.5K]
Not if it ends at 9, like you typed it.
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