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svlad2 [7]
4 years ago
10

A passenger jet in the air increases its speed. does the downward force of air on the top of the wings increase or decrease? doe

s the net lifting force of the air on the wings increase or decrease?
Physics
2 answers:
tresset_1 [31]4 years ago
8 0

Answer:

Downward force on top of the wings decreases.

The net lifting force on the wings increases.

Explanation:

Thinking process:

One of the essential parts of the plan is the wing. The shape of the wing affects the overall drag on the plane.

To a far away view, the wings are flat. However, the closer a person comes ti the plane, the more they see that the shape is different. The wings are curved on top. The underside is flat. This is essential because during take off, the air above the wings moves with faster velocity. The air beneath as lower velocity, hence higher lifting pressure. Thus the plane goes up.

In the air, there is no upward lifting as the plane is steady. Hence there will be a cancellation of forces. Generally, the upward lifting force is higher than the downward force on top of the wings. This results in a plane staying afloat in air.

Vladimir79 [104]4 years ago
6 0
<span>The descending force diminishes that of the net lifting force increments for the fact that air goes over the wings of the aircraft
    Pressure is the typical power per unit region applied by the air on itself and on surfaces that it touches. The lift drive is transmitted through the weight, which acts opposite to the surface of the airfoil. The air keeps up physical contact at all focuses. In this way, the net power shows itself as weight contrasts.</span>
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Mashutka [201]

Sound at 70 dB is 70 dB louder than the human reference level.  That's 10⁷ times as much as the reference sound power.

Sound at 73 dB is 73 dB louder than the human reference level.  That's 10⁷.³  or  2 x 10⁷  times as much as the reference sound power.

Sound at 80 dB is 80 dB louder than the human reference level.  That's 10⁸  or 10 x 10⁷ times as much as the reference sound power.

Now we can adumup:

Intensity of all 3 sources = (10⁷) + (2 x 10⁷) + (10 x 10⁷)

Intensity = (13 x 10⁷) times the sound power reference intensity.

Intensity in dB = 10 log (13 x 10⁷) = 10 (7 + log(13)

Intensity = 70 + 10 log(13)

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Intensity = 70 + 11.14

Intensity = <em>81.14 dB</em>

<em>______________________________________</em>

Looking at the questioner's profile, I seriously wonder whether I'll ever get a comment in return from this creature, and how I'll ever find out if my solution is correct.  For that matter, I'm also seriously questioning how and whether my solution will ever be used for anything.

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