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svlad2 [7]
4 years ago
10

A passenger jet in the air increases its speed. does the downward force of air on the top of the wings increase or decrease? doe

s the net lifting force of the air on the wings increase or decrease?
Physics
2 answers:
tresset_1 [31]4 years ago
8 0

Answer:

Downward force on top of the wings decreases.

The net lifting force on the wings increases.

Explanation:

Thinking process:

One of the essential parts of the plan is the wing. The shape of the wing affects the overall drag on the plane.

To a far away view, the wings are flat. However, the closer a person comes ti the plane, the more they see that the shape is different. The wings are curved on top. The underside is flat. This is essential because during take off, the air above the wings moves with faster velocity. The air beneath as lower velocity, hence higher lifting pressure. Thus the plane goes up.

In the air, there is no upward lifting as the plane is steady. Hence there will be a cancellation of forces. Generally, the upward lifting force is higher than the downward force on top of the wings. This results in a plane staying afloat in air.

Vladimir79 [104]4 years ago
6 0
<span>The descending force diminishes that of the net lifting force increments for the fact that air goes over the wings of the aircraft
    Pressure is the typical power per unit region applied by the air on itself and on surfaces that it touches. The lift drive is transmitted through the weight, which acts opposite to the surface of the airfoil. The air keeps up physical contact at all focuses. In this way, the net power shows itself as weight contrasts.</span>
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Gabriel is performing an experiment in which he is measuring the energy and work being done by a ball rolling down a hill. Which
melamori03 [73]

Answer:

They will both be recorded in Joules

Explanation:

- The energy of an object refers in general to the mechanical energy of the object, which is the sum of its kinetic energy (KE), which is the energy of motion, and of its potential energy (PE), which is the energy due to its position above the ground:

E=PE+KE

- The work done by an object is equal to the product between the force exerted by the object, F, and the displacement, d:

W=Fd (1)

The SI units of the energy is the Joules, J. The basic equivalence with SI units can be seen from the definition of kinetic energy:

KE=\frac{1}{2}mv^2

where

m is the mass, measured in kilograms (kg)

v is the speed, measured in meters per second (m/s)

So we have, since the speed is squared

1 J = 1 kg\cdot \frac{m^2}{s^2}

Now we can check from eq.(1) that the work as the same units. In fact, the force is measured in Newtons (N), and we know that force is equal to mass times acceleration, so we have:

1 N = 1 kg \cdot \frac{m}{s^2}

Distance is measured in meters (m), so the work is measured in

[W]=[kg \cdot \frac{m}{s^2}][m]=[kg\cdot \frac{m^2}{s^2}]

Which corresponds to the definition of Joule. Therefore, both energy and work are measured in Joules.

6 0
4 years ago
Read 2 more answers
.. An object has a mass of 40 000 kilograms
alexgriva [62]

Answer:

8000 kg/cm^3

Explanation:

The density formula is P = M/V

Density = P = ? expressed in kg/m^3

M = mass = 40,000 kg

V = volume = 5 m^3

P = 40,000/5

P = 8000 kg/m^3

6 0
3 years ago
an object of mass 1 g is hung from a spring and set in oscillatory motion .At t=0 the displacement is 43.75cm and the accelerati
charle [14.2K]

The spring constant is 4.0\cdot 10^{-5} N/m

Explanation:

For an object in a simple harmonic motion, the acceleration of the object is related to the displacement by

a=-\omega^2 x

where

a is the acceleration

\omega is the angular frequency

x is the displacement

The angular frequency is defined as

\omega=\sqrt{\frac{k}{m}}

where

k is the spring constant

m is the mass

Substituting the second equation into the first one, we get

a=-\frac{k}{m}x

In this problem we have

m = 1 g = 0.001 kg

And at t=0,

x = 43.75 cm

a = -1.754 cm/s

Therefore, we can re-arrange the equation above to find the spring constant:

k=-\frac{ma}{x}=-\frac{(0.001)(-1.754)}{43.75}=4.0\cdot 10^{-5} N/m

#LearnwithBrainly

6 0
3 years ago
Sobre un gas contenido en un cilindro provisto de un pistón se realiza un trabajo de 7000 Joules, mediante un proceso isotérmico
natita [175]

Answer:

En un proceso isotérmico, es decir, la temperatura no cambia, el trabajo puede escribirse como:

W = n*R*T*Ln(P1/P2)

Donde P1 es la presión inicial y P2 la presión final.

Donde las cantidades:

n =  número de moles

R = constante de los gases ideales

T = temperatura no cambian.

Y sabemos que la ecuación de la energía interna es:

U = C*n*R*T

Donde C es otra constante que depende del gas.

De aca, podemos concluir que ninguna de estas variables cambia en nuestro proceso, por lo que la variación de la energía interna es cero.

U2 - U1 = 0

b) Para el calor cedido o absorbido, la formula básica es:

ΔQ = C*(T2 - T1)

Donde ΔQ es el calor absorbido o cedido por el gas, C es una constante que depende del gas, T2 es la temperatura final del gas y T1 es la temperatura inicial del gas.

Como la temperatura no cambia en el proceso, entonces:

T2 = T1

ΔQ = C*(T2 - T1) = C*0 = 0

No hay calor absorbido ni cedido.

c) Podemos concluir que en un proceso isotérmico la energía interna no cambia, y no hay un intercambio de calor.

8 0
3 years ago
A sky-diver jumps from a stationary balloon. His initial downwards acceleration is 10m/s².
Tatiana [17]

Explanation:

a. The force acting down is gravity, on Earth gravity is 10 m/s^2. When the skydiver jump, the acceleration will start out as -10 m/s^2, but it will eventually equals the air resistance , which is called terminal velocity.

5 0
2 years ago
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