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worty [1.4K]
2 years ago
12

What is an asteroid that is pulled off course by a planet’s gravity and orbits around that planet called?

Physics
1 answer:
tresset_1 [31]2 years ago
4 0

The definition of the celestial bodies allows us to find that the correct answer for a body that is captured and is in planetary orbit is:

  • Moon

Asteroids are small rocky bodies that rotate around the Sun, when this body enters the atmosphere of a planet and reaches the surface it is called meteoroids.

A meteorite is a fragment of meteoroid, which has been divided in space or the atmosphere during the entrance to the planet, in general they are smaller

A meteor is the atmospheric phenomenon that occurs when the pattern meteorite or meteoroid enters, that is, it does not correspond to a celestial body.

An asteroid satellite or Moon is a celestial object that revolves captures and around another asteroid, this concept can be extended to an asteroid revolving captures and around a planet

A satellite is a celestial body that orbits a planet, its origin is varied and could be formed during the formation of the planet itself, or by capturing a nearby body during the initial formation of the solar system.

Let's examine the different answers

  • Moon.

True. A body captured by a planet is generally called the Moon.

  • Meteoriode.

False. A meteoroid is a body that enters the atmosphere of the plant and reaches its surface.

  • Meteorite

False. It is a fragment of meteoroid that manages to reach the surface of the planet.

  • Meteor

False.   Atmospheric phenomenon visible when passing a meteoroid or meteorite.

In conclusion, using the definition of celestial bodies we can find that the correct answer for a body that is captured and is in planetary orbit is:

  • Moon

Learn more here: brainly.com/question/3889451

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an object is producing a sound that has a wavelength in air of 2.69m. If the speed of sound in air is 346m/s, what is the freque
Misha Larkins [42]

Answer:

129.74 Hz

Explanation:

Given:

Wave velocity ( v ) = 346 m / sec

wavelength ( λ ) = 2.69 m

We have to calculate Frequency ( f ) :

We know:

v = λ / t [ f = 1 / t ]

v = λ f

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5 0
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When reaching a boundary between two media (1 and 2), an incident ray is partially reflected and partially refracted. The ray is
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Answer: critical angle, sin^-1 (n2/n1)

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n1 = refractive index of the first medium

n2 = refractive index of the second medium

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When the refrafted ray is perpendicular to the normal, the angle of refraction (θr) is 90° hence making the angle of incidence (θi) the critical angle θc

By substituting these conditions into the Snell's law, we have that

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6 0
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