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worty [1.4K]
2 years ago
12

What is an asteroid that is pulled off course by a planet’s gravity and orbits around that planet called?

Physics
1 answer:
tresset_1 [31]2 years ago
4 0

The definition of the celestial bodies allows us to find that the correct answer for a body that is captured and is in planetary orbit is:

  • Moon

Asteroids are small rocky bodies that rotate around the Sun, when this body enters the atmosphere of a planet and reaches the surface it is called meteoroids.

A meteorite is a fragment of meteoroid, which has been divided in space or the atmosphere during the entrance to the planet, in general they are smaller

A meteor is the atmospheric phenomenon that occurs when the pattern meteorite or meteoroid enters, that is, it does not correspond to a celestial body.

An asteroid satellite or Moon is a celestial object that revolves captures and around another asteroid, this concept can be extended to an asteroid revolving captures and around a planet

A satellite is a celestial body that orbits a planet, its origin is varied and could be formed during the formation of the planet itself, or by capturing a nearby body during the initial formation of the solar system.

Let's examine the different answers

  • Moon.

True. A body captured by a planet is generally called the Moon.

  • Meteoriode.

False. A meteoroid is a body that enters the atmosphere of the plant and reaches its surface.

  • Meteorite

False. It is a fragment of meteoroid that manages to reach the surface of the planet.

  • Meteor

False.   Atmospheric phenomenon visible when passing a meteoroid or meteorite.

In conclusion, using the definition of celestial bodies we can find that the correct answer for a body that is captured and is in planetary orbit is:

  • Moon

Learn more here: brainly.com/question/3889451

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How fast would you be going (in kmh) if you had a ship that accelerated at a constant 1g for 24 hours?
Nady [450]

Answer:

Explanation:

1 g is 9.8 m/s^2 the problem wants the results in km/h so we'll fix that really quick.

9.8 m/s^2 (1 km/1000m)(60 sec/1 min)^2(60 min/1 hour)^2 = 127008 km/hour^2

Now, I'm assuming the ship is starting from rest, and hopefully you know your physics equations.  We are going to use vf = vi + at.  Everything is just given, or we can assume, so I'll just solve.

vf = vi + at

vf = 0 + 127008 km/hour^2 * 24 hours

vf = 3,048,192 km/hour

If there's anything that doesn't make sense let me know.  

5 0
3 years ago
How many different values of ml are possible in the 5d sublevel?
m_a_m_a [10]
<span>There are 5 different values of ml in the 5d sublevel (-2, -1, 0, 1, and 2).</span>
4 0
3 years ago
What is the weight of a spring balance when the point is 30​
andrezito [222]

Answer:

A 30 lb weight is attached to the end of a spring. The spring is stretched 6 in. Find the equation of motion if the weight is released from rest a point 3 inches above equilibrium position 。x(,) =-2 sin(81) 32 x(t) =-32 cos(80 O x(r) =-icos(81)

Explanation:

8 0
2 years ago
A flat coil of wire consisting of 15 turns, each with an area of 40 cm 2, is positioned perpendicularly to a uniform magnetic fi
zheka24 [161]

Answer:

0.54 A

Explanation:

Parameters given:

Number of turns, N = 15

Area of coil, A = 40 cm² = 0.004 m²

Change in magnetic field, ΔB = 5.1 - 1.5 = 3.6 T

Time interval, Δt = 2 secs

Resistance of the coil, R = 0.2 ohms

To get the magnitude of the current, we have to first find the magnitude of the EMF induced in the coil:

|V| = |(-N * ΔB * A) /Δt)

|V| = | (-15 * 3.6 * 0.004) / 2 |

|V| = 0.108 V

According to Ohm's law:

|V| = |I| * R

|I| = |V| / R

|I| = 0.108 / 0.2

|I| = 0.54 A

The magnitude of the current in the coil of wire is 0.54 A

6 0
3 years ago
A spaceship is traveling toward Earth while giving off a constant radio signal with a wavelength of 1 meter (m). What will the s
Nadya [2.5K]

Answer:

Less than 1 m

Explanation:

When objects are getting closer to each other there is a slight change in the wavelength that is being transmitted by either objects. This is known as the blue shift of waves. Here, the wavelength reduces.

In the opposite case the when objects are getting farther from each other there is a slight change in the wavelength that is being transmitted by either objects. This is known as the red shift. Here, the wavelength increases.

In this case the spaceship is getting close to Earth hence the wavelength will be lower than 1 m.

4 0
3 years ago
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