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2 years ago

What is an asteroid that is pulled off course by a planet’s gravity and orbits around that planet called?

1 answer:

4 0

The definition of the celestial bodies allows us to find that the correct answer for a body that is captured and is in planetary orbit is:

Moon

Asteroids are small rocky bodies that rotate around the Sun, when this body enters the atmosphere of a planet and reaches the surface it is called meteoroids.

A meteorite is a fragment of meteoroid, which has been divided in space or the atmosphere during the entrance to the planet, in general they are smaller

A meteor is the atmospheric phenomenon that occurs when the pattern meteorite or meteoroid enters, that is, it does not correspond to a celestial body.

An asteroid satellite or Moon is a celestial object that revolves captures and around another asteroid, this concept can be extended to an asteroid revolving captures and around a planet

A satellite is a celestial body that orbits a planet, its origin is varied and could be formed during the formation of the planet itself, or by capturing a nearby body during the initial formation of the solar system.

Let's examine the different answers

Moon.

True. A body captured by a planet is generally called the Moon.

Meteoriode.

False. A meteoroid is a body that enters the atmosphere of the plant and reaches its surface.

Meteorite

False. It is a fragment of meteoroid that manages to reach the surface of the planet.

Meteor

False. Atmospheric phenomenon visible when passing a meteoroid or meteorite.

In conclusion, using the definition of celestial bodies we can find that the correct answer for a body that is captured and is in planetary orbit is:

Moon

Learn more here: brainly.com/question/3889451

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Your ear is capable of differentiating sounds that arrive at each ear just 0.34 ms apart, which is useful in determining where l

goblinko [34]

Answer:

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

Explanation:

The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.

$\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}$

where,

Δt = required time interval = ?

Δs = distance between ears = 18 cm = 0.18 m

v = speed of sound = 340 m/s

Therefore,

$\Delta t = \frac{0.18\ m}{340\ m/s}$

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

4 0

3 years ago

When you ride a bike and make a turn, you can feel your body trying to

Rina8888 [55]

Answer:first law

Explanation:

it states the a body in motion or rest maintain its state until an external force is acted on it

8 0

3 years ago

The electrical force on a 2-c charge is 60 n. the electric field where the charge is located is

Kazeer [188]

The electrical force acting on a charge q immersed in an electric field is equal to
$F=qE$
where
q is the charge
E is the strength of the electric field

In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:
$E= \frac{F}{q}= \frac{60 N}{2 C}=30 N/C$

5 0

3 years ago

Choose what colors are absorbed when white light hits a red apple. (Pick all that apply.)

astra-53 [7]

A red apple absorbs all colors of visible light except red, so red light
is the only light left to bounce off of the apple toward our eyes.
(This is a big part of the reason that we call it a "red" apple.)

Here's how the various items on the list make out when they hit the apple:

Red . . . . . reflected
Orange . . absorbed
Yellow . . . absorbed
Green . . . absorbed
Blue . . . . absorbed
Violet . . . absorbed
Black . . . no light; not a color
White . . . has all colors in it

4 0

3 years ago

If you push any floating object down from equilibrium and release it, it bobs up and down. That looks like an oscillation, so le

GarryVolchara [31]

Answer:

$F_{y}$ = ( ρ_fluid g A) y

Explanation:

This exercise can be solved in two parts, the first finding the equilibrium force and the second finding the oscillating force

for the first part, let's write Newton's equilibrium equation

B₀ - W = 0

B₀ = W

ρ_fluid g V_fluid = W

the volume of the fluid is the area of the cube times the height it is submerged

V_fluid = A y

For the second part, the body introduces a quantity and below this equilibrium point, the equation is

B - W = m a

ρ_fluid g A (y₀ + y) - W = m a

ρ_fluid g A y + (ρ_fluid g A y₀ -W) = m a

ρ_fluid g A y + (B₀-W) = ma

the part in parentheses is zero since it is the force when it is in equilibrium

ρ_fluid g A y = m a

this equation the net force is

$F_{y}$ = ( ρ_fluid g A) y

we can see that this force varies linearly the distance and measured from the equilibrium position

8 0

2 years ago