Answer:
The maximum height reached by the ball is 2.84 m
Explanation:
Given;
initial velocity of the soccer, u = 13 m/s
angle of projection, θ = 35°
The maximum height reached by the ball = ?
Apply the following kinematic equation, to determine the maximum height reached by the ball.
Maximum height (H) is given as;
Therefore, the maximum height reached by the ball is 2.84 m
D. velocity
Velocity depends on speed and direction
Answer:
v = 10 m/s
Explanation:
given,
Mass of large fish, M = 5 Kg
speed of swimming, v' = 1 m/s
mass of small fish, m = 500 g = 0.5 Kg
speed of the fish = v
using conservation of momentum
m v + M v' = M u' + m u
final speed of both the speed is zero.
- 0.5 x v + 5 x 1 = 0
negative sign is used because small fish is moving in opposite direction.
now,
0.5 v = 5
v = 10 m/s
hence, the speed of the small fish is equal to 10 m/s.
Take 10m/s^2 for the gravitational acceleration, as we know this is a free fall, we can use the equation: d=1/2*g*t^2
Substitute g=10m/s^2, t=5s, d=125m
Wave speed = fλ
=(5 x 10^14)(4 x 10^-7)
=2 x 10^8
Where f is the frequency and λ is the wavelength
