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pav-90 [236]
4 years ago
13

Which compounds are the Bronsted- Lowry bases in the equilibrium?

Chemistry
2 answers:
elena-s [515]4 years ago
6 0

Answer : Option D) H_{2}BO_{3}^{-} and C_{2}O_{4}^{2-}.

Explanation : The acid base theory of Bronsted-Lowry, stated the definition of acids and bases on the basis of conjugated.

The fundamental concept of this theory states that when an acid and a base reacts with each other, the acid forms its conjugate base, and the base forms its conjugate acid by exchanging the proton.

So, in the given reaction;

HC_{2}O_{4}^{-} + H_{2}BO_{3}^{-}  H_{3}BO_{3} + C_{2}O_{4}^{2-}

It is firstly observed that the species H_{2}BO_{3}^{-} is accepting a proton from the acid, therefore this is one of the bases.

Secondly,C_{2}O_{4}^{2-} accepts the proton and forms the reactant again in the reversible reaction.

Therefore, these are the correct options.

H_{2}BO_{3}^{-} and C_{2}O_{4}^{2-}

Butoxors [25]4 years ago
4 0
Its D for plato. 
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4 0
3 years ago
Which of the following has the greatest mass, in grams? 1 atom of lead (Pb) 0.5 mol silver (Ag) atoms 0.3 mol gold (Au) atoms 25
Strike441 [17]

Answer : Option C) 0.3 mol of Gold.

Explanation : Amongst the options given in the question, 0.3 mol of Au is the greatest in mass in grams.

As 0.3 mol X atomic weight of Au (196.966) = 59.088 grams;

Silver has 0.5 mol X atomic weight of Ag (107.86) = 53.93 grams;

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Therefore, it is clear that Au has the greatest mass amongst the given choices.

8 0
4 years ago
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If sugar contains 41.86 carbon and 6.98 hydrogen what percentage of sugar is oxygen
STatiana [176]
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8 0
3 years ago
Calculate the amount, in moles, of each of the following. You may round atomic masses to one decimal place.
Vlada [557]

Answer:

The answer to your question is:

a) 0.023 mol of CdS

b) 0.12 mol of MoO3

c) 7.3 mol of AlPO4

Explanation:

a) CdS

MW = 112.4 + 32

      = 144 g

                                144g ------------------ 1 mol

                                  3.28g --------------  x

                                 x = (3.28 x 1) / 144

                                 x = 0.023 mol

b) MoO3

MW = 96 + 3(16) = 144 g

                              144g -------------------  1 mol

                               17.5g -----------------   x

                               x = (17.5 x 1) / 144

                               x = 0.12 mol

c) AlPO4

MW = 27 + 31 + 4(16)

MW = 122 g

                            122 g ------------------  1mol

                            890 g ------------------   x

                            x = (890 x 1) / 122

                            x = 7.3 mol of AlPO4

7 0
3 years ago
Would an alkaline earth metal make a good replacement for tin in a tin can?
hichkok12 [17]

Answer:

Definitely not. This is because the alkaline earth metal [basically group 2 elements] are reactive and will react with the contents of the can, contaminating it.

4 0
2 years ago
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