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pav-90 [236]
3 years ago
13

Which compounds are the Bronsted- Lowry bases in the equilibrium?

Chemistry
2 answers:
elena-s [515]3 years ago
6 0

Answer : Option D) H_{2}BO_{3}^{-} and C_{2}O_{4}^{2-}.

Explanation : The acid base theory of Bronsted-Lowry, stated the definition of acids and bases on the basis of conjugated.

The fundamental concept of this theory states that when an acid and a base reacts with each other, the acid forms its conjugate base, and the base forms its conjugate acid by exchanging the proton.

So, in the given reaction;

HC_{2}O_{4}^{-} + H_{2}BO_{3}^{-}  H_{3}BO_{3} + C_{2}O_{4}^{2-}

It is firstly observed that the species H_{2}BO_{3}^{-} is accepting a proton from the acid, therefore this is one of the bases.

Secondly,C_{2}O_{4}^{2-} accepts the proton and forms the reactant again in the reversible reaction.

Therefore, these are the correct options.

H_{2}BO_{3}^{-} and C_{2}O_{4}^{2-}

Butoxors [25]3 years ago
4 0
Its D for plato. 
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0.500 mile of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (
SCORPION-xisa [38]

The correct question is as follows: 0.500 moles of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (plz help!)

Answer: The molarity of this solution is 0.25 M.

Explanation:

Molarity is the number of moles of a substance divided by volume in liter.

As it is given that there are 0.5 moles of potassium oxide in 2.00 L of water so, the molarity of this solution is calculated as follows.

Molarity = \frac{moles}{volume(in L)}\\= \frac{0.5 moles}{2.00 L}\\= 0.25 M

Thus, we can conclude that molarity of this solution is 0.25 M.

4 0
2 years ago
Since helium is lighter than air, it is difficult to measure the mass of a sample, so to find out the mass of helium in a birthd
d1i1m1o1n [39]

Answer:

0.7457 g is the mass of the helium gas.

Explanation:

Given:  

Pressure = 3.04 atm

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (25.0 + 273.15) K = 298.15 K  

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

3.04 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K  

<u>⇒n = 0.1863 moles</u>

Molar mass of helium = 4.0026 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.1863\ mole= \frac{Mass}{4.0026\ g/mol}

Mass_{He}= 0.7457\ g

<u>0.7457 g is the mass of the helium gas. </u>

6 0
3 years ago
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