<span>Firstly, we know that M= m/n, the main formula which shows the relationship
between m, n, and M. The nknown compound contains only carbon, hydrogen, and
oxygen, so we can get n(C)=m/M, from M(C)=
m(C)/n (C), besides the stoechiometric
equality, we have </span>
n( C)= m(C)/M(C ) = m(CO2)/ M(CO2)=11/44, because m(CO2)=11.0,
M(CO2)=44.01
so n(C )= 0.24moles,
There are 2 peaks are in the proton spin decoupled 13C NMR spectrum of 1,3,5-trinitrobenzene .
The 13C NMR spectrum give the peak which is directly about the carbon skeleton not just the proton attached to it . The number of signals tell us how many different carbons or set of equivalent carbons . The splitting of a signal tells us how many hydrogens are attached to each carbon.
In 1,3,5-trinitrobenzene molecule , there are 2 peaks are in the proton spin decoupled 13C NMR spectrum three carbon give one signal and another three carbon give another one signal .
To learn more about NMR spectrum
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It is the periodic table
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25.55 grams of tetraphosphorus decaoxide could be produced by the reaction.
Explanation:
First the balanced chemical reaction of the production of tetraphosphorus decaoxide is to be known.
The chemical equation is
10 KClO3 + 3P4⇒ 3 P4010 + 10 KCl
The number of moles of KCLO3 will be calculated by the formula:
number of moles = mass of the compound given ÷ atomic mass of the compound
n = 37.1 ÷ 122.55 ( atomic mass of KClO3 is 122.55 gm/mole)
= 0.30 moles
From the stoichiometry
10 moles of KClO3 is required to produce 3 moles of P4O10
when 0.30 moles of KClO3 is used x moles of P4O10 is formed
thus, 3 ÷ 10 = x ÷ 0.30
= 0.09 moles of KClO3 is produced
To know the mass of P4O10 apply the formula
mass = number of moles × atomic mass
= 0.09 × 283.886 ( atomic mass of P4O10 is 283.88 gram/mole)
= 25.55 grams of P4O10 could be produced.