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VARVARA [1.3K]
3 years ago
10

Nitrogen dioxide gas is produced by the reaction of nitrogen monoxide gas and oxygen gas .

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
8 0
2NO + O2 ----> 2NO2



there ya go
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What is the difference between polyatomic and monatomic compounds??
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Answer:

Monatomic ions are made up of only one atom per ion, whereas polyatomic ions are made up of numerous atoms per ion.

Explanation:

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What is the formula for nitrogen monoxide?
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The answer is NO.

Mono- means 1, so monoxide would indicate that there is 1 oxygen.

The N is double bonded to the O:

N=O

And has an unpaired set of electrons
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25 °C = ________ K <br><br> which one <br> 298<br> 0<br> 33 <br> 197
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Answer:

298

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Explanation:

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7. The equilibrium constant Kc for the reaction H2(g) + I2(g) ⇌ 2 HI(g) is 54.3 at 430°C. At the start of the reaction there are
Juli2301 [7.4K]

Answer:

[H2] = 0.0692 M

[I2] = 0.182 M

[HI] =  0.826 M

Explanation:

Step 1: Data given

Kc = 54.3 at 430 °C

Number of moles hydrogen = 0.714 moles

Number of moles iodine = 0.984 moles

Number of moles HI = 0.886 moles

Volume = 2.40 L

Step 2: The balanced equation

H2 + I2 → 2HI

Step 3: Calculate Q

If we know Q, we know in what direction the reaction will go

Q = [HI]² / [I2][H2]

Q= [n(HI) / V]² /[n(H2)/V][n(I2)/V]

Q =(n(HI)²) /(nH2 *nI2)

Q = 0.886²/(0.714*0.984)

Q =1.117

Q<Kc This means the reaction goes to the right (side of products)

Step 2: Calculate moles at equilibrium

For 1 mol H2 we need 1 mol I2 to produce 2 moles of HI

Moles H2 = 0.714 - X

Moles I2 = 0.984 -X

Moles HI = 0.886 + 2X

Step 3: Define Kc

Kc = [HI]² / [I2][H2]

Kc = [n(HI) / V]² /[n(H2)/V][n(I2)/V]

Kc =(n(HI)²) /(nH2 *nI2)

KC = 54.3 = (0.886+2X)² /((0.714 - X)*(0.984 -X))

X = 0.548

Step 4: Calculate concentrations at the equilibrium

[H2] = (0.714-0.548) / 2.40 = 0.0692 M

[I2] = (0.984 - 0.548) / 2.40 = 0.182 M

[HI] = (0.886+2*0.548) /2.40 = 0.826 M

6 0
3 years ago
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Which of the following is true of group 6A?
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Answer:

The answer to your question is: Includes sulfur and gain two electrons

Explanation:

Includes Chlorine  This option is wrong, Chlorine belongs to group VII.

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Gain 2 electrons . This option is true, Elements in group VI have six valence electrons so they gain to electrons to become estable.

Tend to form +2 ions  This option is wrong, this elements form -2 ions

Have 5 valence electrons This option is wrong, this elements have 6 valence electrons.

7 0
2 years ago
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