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3 years ago

10

Nitrogen dioxide gas is produced by the reaction of nitrogen monoxide gas and oxygen gas .

1 answer:

tensa zangetsu [6.8K]3 years ago

8 0

2NO + O2 ----> 2NO2

there ya go

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What is the [OH-] in a solution if the [H*] = 1.2 x 10-3 M?

spayn [35]

We know that [OH⁻] * [H⁺] = 10⁻¹⁴

plugging the value of [H⁺]

[OH⁻] * 1.2 * 10⁻³ = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ * (10³/1.2)

[OH⁻] = 833.3 * 10⁻¹⁴

[OH⁻] = 8.33 * 10⁻¹²

7 0

3 years ago

Explain how the cardiovascular system helps your body function

zhuklara [117]

Answer:

The blood circulatory system (cardiovascular system) delivers nutrients and oxygen to all cells in the body. It consists of the heart and the blood vessels running through the entire body. The arteries carry blood away from the heart; the veins carry it back to the heart.

Explanation:

You're welcome!

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3 years ago

PLEASE HELP SOMEONE PLEASEEEE

crimeas [40]

Answer:

the answer is b

hope this helps you!!

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3 years ago

A small motor does 4000 J of work in 20 s. What is the power of the motor in watts?

TEA [102]

Answer:

200 W

Explanation:

Formula of Power is

P= W/T

where

W= Work and T= Time

so

4000/20 = 200J/s or 200 W

6 0

3 years ago

Acetylsalicylic acid (aspirin), HC9H7O4, is the most widely used pain reliever and fever reducer. Find the pH of 0.035 M aqueous

KatRina [158]

<u> </u> The pH of 0.035 M aqueous aspirin is 2.48

<u>Explanation:</u>

We are given:

Concentration of aspirin = 0.035 M

The chemical equation for the dissociation of aspirin (acetylsalicylic acid) follows:

$HC_9H_7O_4\rightleftharpoons H^++C_9H_7O_4^-$

<u>Initial:</u> 0.035

<u>At eqllm:</u> 0.035-x x x

The expression of $K_a$ for above equation follows:

$K_a=\frac{[C_9H_7O_4^-][H^+]}{[HC_9H_7O_4]}$

We are given:

$K_a=3.6\times 10^{-4}$

Putting values in above expression, we get:

$3.6\times 10^{-4}=\frac{x\times x}{(0.035-x)}\\\\x=-0.0037,0.0033$

Neglecting the value of x = -0.0037 because concentration cannot be negative

So, concentration of $H^+$ = x = 0.0033 M

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$H^+$ = 0.0033 M

Putting values in above equation, we get:

$pH=-\log(0.0033)\\\\pH=2.48$

Hence, the pH of 0.035 M aqueous aspirin is 2.48

7 0

3 years ago