Answer:
C-O
Explanation:
you have to check the all four bonds and find out their electronegativity difference. Whichever has the largest difference, is your answer.
- N-O = 3.04 - 3.44 = -0.4
- Cl-Cl = 3.16 -3.16 = 0
- C-O = 3.44 - 2.55 = 0.89
- C-H = 2.55 - 2.20= 0.35
Now check the differences, the largest electronegativity differences means the most polar bond
Answer:
mNaCl = mNa + mCl
mNa = 20g
mCl = mCl2/2 = 30/2 = 15g
mNaCl= 20+15 = 35g
when the metal is lost heat and the calorimeter of water is gained the heat
and when the heat lost = the heat gained so,
(M*C*ΔT)m = (M*C*ΔT)w
when Mm= mass of the metal = 30 g
Δ Tm = (80-25) = 55 °C
and Mw = mass of water = 100 g
Cw is the specific heat of water = 4.181 J/g.°C
ΔTw = (25-20) = 5 °C
so by substitution:
∴ 30* Cm*55 = 100 * 4.181 * 5
∴Cm (specific heat of metal) = (100*4.181*5)/(30*55)
∴C of metal = 1.267 J/g.°C
Answer:
2.28 m
Explanation:
Use the relationship
λ=vf
to solve for wavelength λ. Substituting the known quantities yields:
λ=vf
λ=2.99 x 108 m/s1.31 x 108 Hz
λ=2.28 m
