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steposvetlana [31]
3 years ago
7

What is the wavelength range,in nanometer,for infrared light? In what portion of this range does the earth receive IR from the s

un? What are the wavelength limits for the thermal IR range?
Chemistry
1 answer:
andrezito [222]3 years ago
7 0
  • The wavelength range of Infrared radiation is 700 nanometers to 1 millimeter.
  • The sun emits mainly near-infrared which is mainly composed of wavelength below 4 micrometers.
  • The thermal range of infrared ranges between wavelengths 3.5 and 2.0 micrometers

Explanation:

The wavelength range of Infrared radiation is 700 nanometers to 1 millimeter. This also translates to a frequency range of 430 TeraHertz  to 300 Giga Hertz.

Because the sun is a star and is hot in comparison to earth and other planetary bodies, the bigger  range of infrared radiation it emits is in the near-infrared which is mainly composed of wavelength below 4 micrometers.

The earth's surface produces infrared radiation of the mid-infrared range while cooler substances will produce far-infrared range

The thermal range of infrared ranges between wavelengths 3.5 and 2.0 micrometers and is produced by black bodies.

Learn More:

For more on infrared radiation check out;

brainly.com/question/2369243

#LearnWithBrainly

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Write the mole ratios of (2ca+o2➡2cao)
tresset_1 [31]
N(Ca)/2 = n(O)/1 = n(CaO)/2

The calcium and the Calcium Oxide are divided by 2 because of their coefficients
there is no number in front of the oxygen so it is over one.
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6 0
3 years ago
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0.475 g H, 7.557 gS, 15.107 g O. Express your answer as a chemical formula.
max2010maxim [7]

Answer:

H₂SO₄

Explanation:

We have a compound formed by 0.475 g H, 7.557 g S, 15.107 g O. In order to determine the empirical formula, we have to follow a series of steps.

Step 1: Calculate the total mass of the compound

Total mass = mass H + mass S + mass O = 0.475 g + 7.557 g + 15.107 g

Total mass = 23.139 g

Step 2: Determine the percent composition.

H: (0.475g/23.139g) × 100% = 2.05%

S: (7.557g/23.139g) × 100% = 32.66%

O: (15.107g/23.139g) × 100% = 65.29%

Step 3: Divide each percentage by the atomic mass of the element

H: 2.05/1.01 = 2.03

S: 32.66/32.07 = 1.018

O: 65.29/16.00 = 4.081

Step 4: Divide all the numbers by the smallest one

H: 2.03/1.018 ≈ 2

S: 1.018/1.018 = 1

O: 4.081/1.018 ≈ 4

The empirical formula of the compound is H₂SO₄.

7 0
3 years ago
In one experiment, the reaction of 1.00 mercury and an excess of sulfur yielded 1.16g of a sulfide of mercury
Nuetrik [128]

<u>Answer and Explanation:</u>

Mercury combines with sulfur as follows -

Hg + S = HgS

Hg = 200,59

S = 32,066 Therefore 1.58 g of Hg will react with -

1.58 multiply with 32,066 divide by 200,96 of sulfur.

= 0.25211 g S

This will form 1.58 + 0.25211 g HgS  = 1.83211 g HgS

The amount of S remaining = 1.10 - 0.25211  = 0.84789 g

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It is a period.....
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harkovskaia [24]

Answer:

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6 0
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