The summation of the considered expression in terms of n from n = 1 to 14 is given by: Option D: 343
<h3>How to find the sum of consecutive integers?</h3>

<h3>
What are the properties of summation?</h3>
![\sum_{i=r}^s (a \times f(i) + b) = a \times [\: \sum_{i=r}^s f(i)] + (s-r)b](https://tex.z-dn.net/?f=%5Csum_%7Bi%3Dr%7D%5Es%20%20%28a%20%5Ctimes%20f%28i%29%20%2B%20b%29%20%3D%20a%20%5Ctimes%20%5B%5C%3A%20%5Csum_%7Bi%3Dr%7D%5Es%20f%28i%29%5D%20%2B%20%28s-r%29b)
where a, b, r, and s are constants, f(i) is function of i, i ranging from r to s (integral assuming).
For the given case, the considered summation can be written symbolically as:

It is evaluated as;
![\sum_{n=1}^{14} (3n + 2) = 3 \times [ \: \sum_{n=1}^{14} n ] + \sum_{n=1}^{14} 2\\\\\sum_{n=1}^{14} (3n + 2) = 3 \times \dfrac{(14)(14 + 1)}{2} + (2 + 2 + .. + 2(\text{14 times}))\\\\\sum_{n=1}^{14} (3n + 2) = 3 \times 105 + 28 = 343\\](https://tex.z-dn.net/?f=%5Csum_%7Bn%3D1%7D%5E%7B14%7D%20%20%283n%20%2B%202%29%20%3D%203%20%5Ctimes%20%5B%20%5C%3A%20%5Csum_%7Bn%3D1%7D%5E%7B14%7D%20n%20%5D%20%2B%20%5Csum_%7Bn%3D1%7D%5E%7B14%7D%202%5C%5C%5C%5C%5Csum_%7Bn%3D1%7D%5E%7B14%7D%20%20%283n%20%2B%202%29%20%3D%203%20%5Ctimes%20%5Cdfrac%7B%2814%29%2814%20%2B%201%29%7D%7B2%7D%20%2B%20%282%20%2B%202%20%2B%20..%20%2B%202%28%5Ctext%7B14%20times%7D%29%29%5C%5C%5C%5C%5Csum_%7Bn%3D1%7D%5E%7B14%7D%20%20%283n%20%2B%202%29%20%3D%203%20%5Ctimes%20105%20%2B%2028%20%3D%20343%5C%5C)
Thus, the summation of the considered expression in terms of n from n = 1 to 14 is given by: Option D: 343
Learn more about summation here:
brainly.com/question/14322177
We know that
<span>the formula used to calculate the standard deviations of sample data is
</span><span>is the one shown in the attached figure
</span>
therefore
the answer is the first option
Subtract 14x from both sides to get

Subtract 12 from both sides to get

Now we have moved all terms involving x on one side, and all constant terms on the other. We can simplift both sides, i.e. sum like terms, to get

Now we have to divide both sides by 6. When dealing with inequality you have to be careful about dividing both sides by the same constant: if the constant is negative, the inequality side switches (i.e.
). But this is not the case since 6 is positive, so we mantain the inequality sign:
on the other. We can simplift both sides, i.e. sum like terms, to get

Evaluate left and right hand side:

So he gives 1/4 to his brother 220/4=55 then then he sells the 20% which is 220*.20=44 and then 15 he takes to his friends so if you add those you get 55+44=99+15=114 then subtract this number from the total 220-114=106