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VikaD [51]
4 years ago
7

Which of the following are solutions to the equations below? x^2+x-20=0

Mathematics
2 answers:
Sveta_85 [38]4 years ago
5 0

Answer:

x=4  x=-5

Step-by-step explanation:

x^2+x-20=0

Factor

What 2 numbers multiply to -20 and add to 1

-4*5 =-20 and

-4+5 =1

(x-4) (x+5) =0

Using the zero product property

x-4 =0  x+5=0

x=4  x=-5

irinina [24]4 years ago
4 0

Answer:My answer would be

x=4,-5

tell me if I am wrong


Step-by-step explanation:


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Find angle X in the angle diagram.
miss Akunina [59]

Answer:

80*

Step-by-step explanation:

Angle x + 80* add up to the vertical angle of 160*

So, 160* = x + 80*

80* = x

5 0
3 years ago
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Denzel makes $4,800 at her job. Next month, her salary will increase by 3%.
Pachacha [2.7K]
She will make 4944 dollars because 3% of 4800 is 144 and when you add 4800 and 144 you get 4944
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4x-5y=-15 <br> 7x-2y=21 <br> X=<br> Y=
Helen [10]

Answer:

The values of x and y to the given equations are x=5 and y=7

Step-by-step explanation:

Given equations are 4x-5y=-15\hfill (1)

7x-2y=21\hfill (2)

To solve the given equations by elimination method :

Multiply the equation (1) into 2 we get

8x-10y=-30\hfill (3)

Multiply the equation (2) into 5 we get

35x-10y=105\hfill (4)

Now subtracting the equations (3) and (4) we get

8x-10y=-30

35x-10y=105

_________________

-27x=-135

x=\frac{135}{27}

Therefore x=5

Now substitute the value of x=5 in equation (1) we get

4(5)-5y=-15

20-5y=-15

-5y=-15-20

-5y=-35

y=\frac{35}{5}

Therefore y=7

The values are x=5 and y=7

4 0
3 years ago
Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
Rewrite p(x)=x(x-1)+1 in standard form
mario62 [17]
Answer : p(x)= x^2 -x+1

*Mark brainliest*
5 0
3 years ago
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