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gtnhenbr [62]
3 years ago
7

What is the slope of a line that passes through (–12,15) and (0,4)?

Mathematics
2 answers:
Dmitrij [34]3 years ago
6 0
Slope for points (x1,y1) and (x2,y2)
slope=(y2-y1)/(x2-x1)

(x,y)
(-12,15)
(0,4)

x1=-12
y1=15
x2=0
y2=4

slope=(4-15)/(0-(-12))=-11/(0+12)=-11/12


slope=-11/12
Romashka [77]3 years ago
5 0
I think that the answer is negative 11 over 12
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2x+5y=-13 <br> 3x-5y=14<br><br> Solve for x and y
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Answer:

I got x= 1/5 and y= -67/25 (sorry if it is wrong)

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12 plus the product of 2 and some number is equal to the product of 4 and some number minus 8 .
geniusboy [140]

Answer:

The number is 10

Step-by-step explanation:

Let x be the number

product is multiply

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Researchers are interested if a school breakfast program leads to taller children. Assume that the population of all 5 year-old
DedPeter [7]

Answer:

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=39 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1 represent the population standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

And replacing we got:

ME= 1.96 *\frac{1}{\sqrt{25}}= 0.392

Now we have everything in order to replace into formula (1):

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

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