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Katarina [22]
3 years ago
8

The first term of a sequence is -12. The recursive formula for the sequence is an = an-1 + 9. What are the next 3 terms in the s

equence?
Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0
Hello :
by : <span>an = an-1 + 9. 
n= 2 : a2 =a1+9
         a2 = -12+9 = -3
n=3 : a3 = a2 +9 
        a3 = -3+9 = 6
n = 4 : a4 = a3 +9
           a4 =6+9 = 15</span>
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If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
erma4kov [3.2K]

Answer:

\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

Step-by-step explanation:

Given

5 tuples implies that:

n = 5

(h,i,j,k,m) implies that:

r = 5

Required

How many 5-tuples of integers (h, i, j, k,m) are there such thatn\ge h\ge i\ge j\ge k\ge m\ge 1

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed:  This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

^{n}C_r => ^{n + 4}C_5

^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}

^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}

Expand the numerator

^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

<u><em>Solved</em></u>

6 0
3 years ago
3 2/3 = 2 + N/3 solve for N
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If the question is 3*2/3=2+N/3
N=0

If the question is 2/3=2+N/3
N=-4
3 0
3 years ago
Currently, in Littlefield, jobs arrive at 12 per day and you have (just) enough capacity at each station (i.e., the departure ra
OlgaM077 [116]

Answer:

The WIP limit is 0.50 days.

Step-by-step explanation:

The Computation of WIP limits:

to begin with, it is required to compute the process and procedure efficiency which will be computed as follows:

Value Added Time = 12 days (arriving time)

Non-Value-Added Time = 12 days (departure time)

Efficiency = Value Added / (Value Added + Non-Value Added)

                = 12 / (12+12)

                = 12 / 24

               = 0.50 or 50%

the most obligatory throughput time will be 0.25 days to realize the profits

WIP limit = Throughput time / Efficiency  

               = 0.25 / 50%

               = 0.50 days.

The WIP limit is 0.50 days.

6 0
3 years ago
Which model represent the factors of 4x2-9
lions [1.4K]

Step-by-step explanation:

4x²-9

4x²+6x-6x-9

4x²+6x-6x-9

2x(2x+3)-3(2x+3)

2x(2x+3)-3(2x+3)

(2-3)(2x+3)

solution

(8x-3)(2x+3)

6 0
2 years ago
Sheila, janice, and katen, working together at the same rate, can complete a job in 3 1/3 days. Working at the same rate, how mu
pychu [463]

Answer:

Janice and Karen could do in 1 day:

  • <u>20% of the job</u>.

Step-by-step explanation:

To identify how much of the job could janice and caren do in 1 day, first, we must find how much of the job make just 1 person at the same rate:

If three persons make a job in 3 1/3 days, 1 person make the job in x:

  • 3 persons ⇒ 3 1/3 days or 10/3 days
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Then:

  • x=\frac{1 person*\frac{10}{3}days }{3 persons} (we cancel the unit "persons")
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Just a person would need 10 days to complete a job, now, we're gonna divide this value in 2 to obtain the time that need two persons to complete a job:

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How two persons need 5 days to complete a job (in this case, the two persons are Janice and Karen), we can make a simple rule of three to obtain the percentage made in 1 day:

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Then:

  • x=\frac{1*100}{5} (you can use the % if you want, the result is the same)
  • x=\frac{100}{5}
  • x=20

As you can see, <u><em>Janice and Karen just in a day could do 20% of the job</em></u>.

3 0
3 years ago
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