Question

The amplitude of the electric field of an electromagnetic wave traveling in a vacuum is measured to be 3.5 x 10^2 v/m. What is the amplitude of the magnetic field in this wave?

Answer 1

Answer:$B=1.166 \times 10^{-6} T$

Explanation:

Given

Amplitude of Electric field is $3.5\times 10^2$

We know the relation between Electric field and Magnetic field is

E=cB

Where

E=Electric Field

c=speed of light

B=Magnetic field

$B=\frac{E}{c}$

$B=\frac{3.5\times 10^2}{3\times 10^8}$

$B=1.166 \times 10^{-6} T$