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-BARSIC- [3]
3 years ago
13

You place a box weighing 253.1 N on an inclined plane that makes a 39.7◦ angle with the horizontal.

Physics
1 answer:
Masja [62]3 years ago
7 0

Answer:

Explanation:

The weight of the box is

W = 253.1N

Weight is on an incline plane

θ = 39.7°

The weight of an object is always acting downward

So, the weight makes an angle of 39.7° with the vertical component

Then, it's horizontal component is

Wx = W•Sinθ

Wx = 253.1 × Sin 39.7°

Wx = 161.67 N

The horizontal component of the weight is 161.67N

This is the force acting down the plane.

Check attachment

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Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p
Marta_Voda [28]

Answer:

Acceleration, a=9.91\times 10^{15}\ m/s^2

Explanation:

It is given that,

Separation between the protons, r=3.73\ nm=3.73\times 10^{-9}\ m

Charge on protons, q=1.6\times 10^{-19}\ C

Mass of protons, m=1.67\times 10^{-27}\ kg

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

ma=\dfrac{kq^2}{r^2}

a=\dfrac{kq^2}{mr^2}      

a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}      

a=9.91\times 10^{15}\ m/s^2

So, the acceleration of two isolated protons is 9.91\times 10^{15}\ m/s^2. Hence, this is the required solution.

3 0
3 years ago
Santa doesn't want to push a 25.0 kg wooden box across a wooden floor with a uk of 0.20 at
scZoUnD [109]

Answer:

49 N

Explanation:

In order to move the box at constant speed, the acceleration of the box must be zero (a=0): this means, according to Newton's second law,

F = ma

that the net force acting on the box, F, must be zero as well.

Here there are two forces acting on the box in the horizontal direction while it is moving:

- The force of push applied by the guy, F

- The frictional force, F_f

For an object moving on a flat surface, the frictional force is given by

F_f = \mu_k mg

where

\mu_k is the coefficient of friction

m is the mass of the box

g is the acceleration of gravity

So the equation of the forces becomes

F-\mu_k mg = 0

And substituting:

\mu_k = 0.20\\m = 25.0 kg\\g = 9.8 m/s^2

We find the force that must be applied by the guy:

F=\mu_k mg = (0.20)(25.0)(9.8)=49 N

6 0
2 years ago
Energy captured during the ""photo"" part of photosynthesis is stored in _____ during the ""synthesis"" part of the process.
andre [41]

Energy captured during the ""photo"" part of photosynthesis is stored in  <u>covalent bond</u> during the ""synthesis"" part of the process.

<u>Explanation:</u>

When carbon dioxide, water and sunlight are combindly processed by Plants, algae and a set of bacteria called cyanobacteria to become photoautotrophs, then the process goes is named as Photosynthesis. It generates oxygen, Glyceraldehyde-3-phosphate (G3P), common high-energy carbohydrate molecules which result into glucose, sucrose or other sugar molecules which comprises covalent energy-saving bonds.

Thus the species breakdown these molecules to exhibit energy for cellular functioning. In light-dependent processes, chlorophyll absorbs the radiation from the sunlight and converts it into chemical energy in the form of electron carrier derivatives such as ATP and NADPH. Carbohydrate molecules are constructed from carbon dioxide in light-independent processes i.e in the Calvin cycle, using the chemical energy obtained throughout the light-dependent processes.

5 0
3 years ago
What would be the kinetic energy of an arrow having a potential energy of 50 J after it is shot from a bow?
klasskru [66]

Answer:

The kinetic energy of the arrow is equaled to the potential energy of the stretching of the bow, which in this case is 50 J.

Explanation:

Potential energy converts to kinetic as soon as it begins to move.

3 0
2 years ago
A 65.0-kg woman steps off a 10.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 3.40 m,
babymother [125]

Answer:

19372.29 N

Explanation:

Kinetic Energy of the man = Work done by the average resistive force of water.

mg(H+d) = F×d............................ Equation 1

where, m = mass of the woman, H = Height of the platform, d = depth of water reached, F = average resistive force exerted by water.

make F the subject of the equation,

F = mg(H+d)/d...................... Equation 2

Given: m = 65.0 kg, H = 10 m, d = 3.4 m, g = 9.8 m/s²

Substitute into equation 2

F = 65(9.8)(100+3.4)/3.4

F = 19372.29 N

8 0
3 years ago
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