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-BARSIC- [3]
3 years ago
13

You place a box weighing 253.1 N on an inclined plane that makes a 39.7◦ angle with the horizontal.

Physics
1 answer:
Masja [62]3 years ago
7 0

Answer:

Explanation:

The weight of the box is

W = 253.1N

Weight is on an incline plane

θ = 39.7°

The weight of an object is always acting downward

So, the weight makes an angle of 39.7° with the vertical component

Then, it's horizontal component is

Wx = W•Sinθ

Wx = 253.1 × Sin 39.7°

Wx = 161.67 N

The horizontal component of the weight is 161.67N

This is the force acting down the plane.

Check attachment

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Which of these is emitted during beta decay ?
satela [25.4K]

Answer:

C. a small charged particle.

Explanation:

typically beta radiation emits an electron which is a small negativity charged particle.

hope it helps. :)

4 0
2 years ago
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2. A test reveals that 150 J of work is required to lift an object 3 m at a
Nuetrik [128]

Answer:

50N

Explanation:

W=Fd

150=F(3)

50N=F

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2 years ago
In a physics lab experiment for the determination of moment of inertia, a team weighs an object and finds a mass of 2.15 kg. The
Maksim231197 [3]

Answer:

0.339 kgm²

Explanation:

We know the period of this pendulum, T = 2π√(I/mgh) where I = moment of inertia of the object about the pivot axis, m = mass of object = 2.15 kg, g = acceleration due to gravity = 9.8 m/s² and h = distance of center of mass of object from pivot point = 0.163 m.

Since T = 2π√(I/mgh), making I subject of the formula, we have

I = mghT²/4π²

Now since it takes 241 s to complete 113 cycles, then it takes 241 s/113 cycles to complete one cycle.

So, T = 241 s/113 = 2.133 s

So, Substituting the values of the variables into I, we have

I = mghT²/4π²

I = 2.15 kg × 9.8 m/s² × 0.163 m × (2.133 s)²/4π²

I = 15.63/4π² kgm²

I = 0.396 kgm²

Now from the parallel axis theorem, I = I' + mh² where I' = moment of inertia of object with respect to its center of mass about an axis parallel to the pivot axis

I' = I - mh²

I' = 0.396 kgm² - 2.15 kg × (0.163 m)²

I' = 0.396 kgm² - 0.057 kgm²

I' = 0.339 kgm²

7 0
3 years ago
An 850 kg elevator is accelerating upwards at 3.0 m/s2. Calculate the tension in the cable.
sveta [45]

Answer:

10880N

Explanation:

We are given that

Mass of elevator, m=850 kg

Acceleration, a=3m/s^2

g=9.8m/s^2

We have to find the tension in the cable.

We know that

When elevator is accelerating upward then tension in the cable

T=m(a+g)

Using the formula

T=850(3+9.8)

T=10880N

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2 years ago
Why are electromagnets more useful than permanent magnets in many
Likurg_2 [28]

Answer: Electromagnets can be turned on and off by controlling the current

Explanation:

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