Answer:
The answer is 1.87nm/s.
Explanation:
The 
water loss must be replaced by of sap. 110g of sap corresponds to a volume of
thus rate of sap replacement is
The volume of sap in the vessel of length 
is
,
where 
is the cross sectional area of the vessel.
For 2000 such vessels, the volume is
taking the derivative of both sides we get:
on the left-hand-side 
is the velocity 
of the sap, and on right-hand-side 
; therefore,
and since the cross-sectional area is
;
therefore,
solving for we get:
which is the upward speed of the sap in each vessel.
You could cook it and then drop it or you can always wrap it in bubble wrap.
Answer:
6.75m
Explanation:
To calculate the distance in this question, we can use the formula:
S = ut + 1/2at^2
Where; S = distance
u = initial velocity = 0m/s
t = 3s
a = 1.5m/s^2
Hence:
S = (0 × 3) + 1/2 (1.5 × 3 × 3)
S = 0 + 1/2 (13.5)
S = 13.5/2
S = 6.75
Therefore, the car will travel 6.75m in 3seconds.
Of course in as the Earth make a full revolution we see the sun and no stars except the sun and when our section of Earth is facing away from the sun we can see other starts
also as the Earth revolves around the sun certain start can be seen and certain start go out of view<span />
Answer:
Explanation:
For image formation in objective lens
object distance u = 14 +1 = 15 mm
focal length f = 14 mm .
image distance v = ?
lens formula
Putting the values
v = 210 mm .
B )
magnification = v / u
= 210 / 15
= 14
size of image = 14 x 1.1 mm
= 15.4 mm
= 15 mm approx
C )
For final image to be at infinity , image produced by objective lens must fall at the focal point of eye piece . so objective lens's distance from the image formed by objective must be equal to focal length of eye piece that is 21 mm .
21 mm is the answer .
D )
overall magnification =
D = 25 cm , f_e = focal length of eye piece
= 14 x 250 / 21
= 166.67
= 170 ( in two significant figures )
