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3 years ago

Which of the following is not true about the Law of Conservation of Energy?

Physics

2 answers:

SVEN [57.7K]3 years ago

8 0

By definition, the law of conservation of energy states that:

Ei = Ef

Where,

Ei: initial energy

Ef: final energy

Therefore, no matter the type of energy, always the final energy is equal to the final energy.

Energy can be transformed into another type of energy. For example, the potential energy can be transformed into kinetic energy.

Also, energy is not created, nor destroyed.

Answer:

The following is not true about the Law of Conservation of Energy:

A. It states that the total energy in the universe keeps increasing.

goldenfox [79]3 years ago

8 0

A, it states that the total energy in the universe keeps increasing.

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Sunlight shines through a salt shaker. Should you expect more, less, or the same amount of scattering from blue light compared t

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Blue light will scatter more compared to red light.

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<h3>What is scattering of light?</h3>

Scattering of light is the phenomenon in which light rays deviate from their original path upon striking an obstacle like dust, gas molecules or water vapors. Scattering of light gives rise to many spectacular phenomena such as Tyndall effect and the red hues that can be seen at sunrise and sunset.

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2 years ago

A body of mass 2.7 kg makes an elastic collision with another body at rest and continues to move in the original direction but w

kramer

Answer:

1.35 kg

2.67 ms⁻¹

Explanation:

$m_{1}$ = mass of first body = 2.7 kg

$m_{2}$ = mass of second body = ?

$v_{1i}$ = initial velocity of the first body before collision = $v$

$v_{2i}$ = initial velocity of the second body before collision = 0 m/s

$v_{1f}$ = final velocity of the first body after collision =

using conservation of momentum equation

$m_{1} v_{1i} + m_{2} v_{2i} = m_{1} v_{1f} + m_{2} v_{2f}\\(2.7) v + m_{2} (0) = (2.7) (\frac{v}{3} ) + m_{2} v_{2f}\\(2.7) (\frac{2v}{3} ) = m_{2} v_{2f}\\v_{2f} = \frac{1.8v}{m_{2}}$

Using conservation of kinetic energy

$m_{1} v_{1i}^{2}+ m_{2} v_{2i}^{2} = m_{1} v_{1f}^{2} + m_{2} v_{2f}^{2} \\(2.7) v^{2} + m_{2} (0)^{2} = (2.7) (\frac{v}{3} )^{2} + m_{2} (\frac{1.8v}{m_{2}})^{2} \\(2.7) = (0.3) + \frac{3.24}{m_{2}}\\m_{2} = 1.35$

$m_{1}$ = mass of first body = 2.7 kg

$m_{2}$ = mass of second body = 1.35 kg

$v_{1i}$ = initial velocity of the first body before collision = 4 ms⁻¹

$v_{2i}$ = initial velocity of the second body before collision = 0 m/s

Speed of the center of mass of two-body system is given as

$v_{cm} = \frac{(m_{1} v_{1i} + m_{2} v_{2i})}{(m_{1} + m_{2})}\\v_{cm} = \frac{((2.7) (4) + (1.35) (0))}{(2.7 + 1.35)}\\\\v_{cm} = 2.67$ ms⁻¹

8 0

3 years ago

A stable, binary ionic compound exists where the cation (A) has a charge twice in magnitude than that of the anion (X). What wou

svetlana [45]

<span>The cation is positively charged and has a charge twice that of the anion, for example +2. The anion is negatively charged and in our example where the cation has a +2 charge, it must have a -1 charge. In order for the charges to equal zero, there must be two anions: -1 x 2 = -2 So the answer is D. AX2</span>

8 0

3 years ago

Read 2 more answers

A wave has a wavelength of 7 mm and a frequency of 19 hertz. What is its speed?

ASHA 777 [7]

Speed = (frequency) x (wavelength)

Speed = (19 per second) x (7 mm)

Speed = (19 x 7) (per second · mm)

<em>Speed = 133 mm/sec</em>

or you might want to write <em>Speed = 0.133 m/s</em> .

4 0

3 years ago