Answer:
velocity at the top: 0 m/s
acceleration at the top: -9.8 m/s²
Explanation:
Assuming up is positive and down is negative;
The velocity of the ball at the top of its path will be 0 m/s and the acceleration will be negative.
The velocity is 0 m/s because the ball does not move at the top of its path, and it switches from a positive velocity to a negative velocity. It must go through 0 in order to go from positive to negative.
The acceleration, however, is always negative no matter where the ball is in its motion. This negative acceleration causes the ball to slow down as it reaches the top, and speed up as it reaches the bottom.
<u>Think about it:</u> If there wasn't a negative acceleration, and it was instead 0, the ball would never come back down and instead keep going in a straight line.
Answer:
According to the Newton's law of gravitational every object in the universe attracts every other objects with a force which is called gravitational force.This gravitational force is (i) directly proportional to the product of their masses and (ii) inversely proportional to the square of the distance between their centres.
Explanation:
Newton's law of gravitational is called the universal law because it is applicable to all the bodies either terrestrial or celestial having any shape,size,mass or at any distance apart with any medium between them,at any time(past,present or future).
Answer:
![|D_{depth} |=19.697m](https://tex.z-dn.net/?f=%7CD_%7Bdepth%7D%20%7C%3D19.697m)
Explanation:
To find Depth D of lake we must need to find the time taken to hit the water.So we use equation of simple motion as:
Δx=vit+(1/2)at²
![x_{f}-x_{i}=v_{i}t+(1/2)at^{2}\\ -5.0m=(o)t+(1/2)(-9.8m/s^{2} )t^{2}\\ -4.9t^{2}=-5.0\\ t^{2}=5/4.9\\t=\sqrt{1.02} \\t=1.01s](https://tex.z-dn.net/?f=x_%7Bf%7D-x_%7Bi%7D%3Dv_%7Bi%7Dt%2B%281%2F2%29at%5E%7B2%7D%5C%5C%20%20-5.0m%3D%28o%29t%2B%281%2F2%29%28-9.8m%2Fs%5E%7B2%7D%20%29t%5E%7B2%7D%5C%5C%20-4.9t%5E%7B2%7D%3D-5.0%5C%5C%20t%5E%7B2%7D%3D5%2F4.9%5C%5Ct%3D%5Csqrt%7B1.02%7D%20%5C%5Ct%3D1.01s)
As we have find the time taken now we need to find the final velocity vf from below equation as
![v_{f}=v_{i}+at\\v_{f}=0+(-9.8m/s^{2} )(1.01s) \\v_{f}=-9.898m/s](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7Bi%7D%2Bat%5C%5Cv_%7Bf%7D%3D0%2B%28-9.8m%2Fs%5E%7B2%7D%20%29%281.01s%29%20%5C%5Cv_%7Bf%7D%3D-9.898m%2Fs)
So the depth of lake is given by:
first we need to find total time as
t=3.0-1.01 =1.99 s
![|D_{depth} |=|vt|\\|D_{depth} |=|(-9.898m/s)(1.99s)|\\|D_{depth} |=19.697m](https://tex.z-dn.net/?f=%7CD_%7Bdepth%7D%20%7C%3D%7Cvt%7C%5C%5C%7CD_%7Bdepth%7D%20%7C%3D%7C%28-9.898m%2Fs%29%281.99s%29%7C%5C%5C%7CD_%7Bdepth%7D%20%7C%3D19.697m)
Answer:
Your answer here is D
Explanation:
Slowly pressing your breaks will help ensure you are not hit by the other car. If they hit you its their fault. Hope this helps :)!
Answer:
one-third of its weight on Earth's surface
Explanation:
Weight of an object is = W = m*g
Gravity on Earth = g₁ = 9.8 m/s
Gravity on Mars = g₂ =
g₁
Weight of probe on earth = w₁ = m * g₁
Weight of probe on Mars = w₂ = m * g₂ -------- ( 1 )
As g₂ = g₁/3 --------- ( 2 )
Put equation (2) in equation (1)
so
Weight of probe on Mars = w₂ = m * g₁ /3
Weight of probe on Mars =
m * g₁ =
w₁
⇒Weight of probe on Mars =
Weight of probe on earth