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11Alexandr11 [23.1K]
3 years ago
13

It would be enchanting if you could help me out on this question, pease and crackers. thank you!(don't mind my weird language lo

l)

Mathematics
1 answer:
Alina [70]3 years ago
5 0

Answer:

615.44cm

Step by Step Answer:

A=πr^{2}=π·14^{2}≈615.75216

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Can someone help me
mafiozo [28]
If you need to you can write it out. the answer is X=14

5 0
3 years ago
What is 2+2 in math and the answer is 4
Marianna [84]

Answer:

4

Step-by-step explanation:

7 0
3 years ago
Solve 3y - 15 = y+1 with steps shown
bija089 [108]

Answer:

y = 8

Step-by-step explanation:

Hello!

We can solve for y by isolating it.

<h3>Solve for y</h3>
  • 3y - 15 = y + 1
  • 3y - 15 - y = y +1 - y
  • 2y - 15 = 1
  • 2y - 15 + 15 = 1 + 15
  • 2y = 16
  • y = 16/2
  • y = 8

The value of y is 8.

4 0
2 years ago
Read 2 more answers
200 children attended the school play. Of the total attendance, 40% were boys. How many
vesna_86 [32]

Answer:

120

Step-by-step explanation:Do you hundred times 40% equals 80. 200-80 = 120 which is the number of girls that attended.

5 0
3 years ago
We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure
STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be h(t) = -16\cdot t^{2} + 128\cdot t + 320, the first and second derivatives are, respectively:

First Derivative

h'(t) = -32\cdot t +128

Second Derivative

h''(t) = -32

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

-32\cdot t +128 = 0

t = \frac{128}{32}\,s

t = 4\,s (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320

h(4\,s) = 576\,ft

The highest altitude that the object reaches is 576 feet.

6 0
4 years ago
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