Answer:
There are 10 boys and 6 girls in the class
Step-by-step explanation:
The given parameters are;
The number of boys = The number of girls + 4
The number of students in the class = 16
Let x represent the number of girls in the class and let y represent the number of boys in the class
Therefore;
y = x + 4...(1)
x + y = 16...(2)
Making y the subject of equation (2) gives;
y = 16 - x
Equating the values of y from equation (1) and equation (2) gives;
x + 4 = 16 - x
Which gives;
2·x = 16 - 4 = 12
x = 12/2 = 6
x = 6
The number of girls = x = 6
From equation (1), we have;
y = x + 4 = 6 + 4 = 10
y = 10
The number of boys = y = 10.
I believe the answer is B but I’m nah for sure
1 ≤ 3 - x
x + 1 ≤ 3 <em>added x to both sides</em>
x ≤ 2 <em>subtracted 1 from both sides</em>
Number line: ←----------------------·2 (fill in the dot at 2 since it is "equal to")
Interval Notation: (-∞, 2]
Answer:
See the explanations below
Step-by-step explanation:
Given the function y = x²+12x
We are to find the inverse and identify the error in the calculation:
Step 1: Replace y with x
x = y²+12y
First Error: There is an error here y, the variable attached to x should be y and not x that is y = y²+12y and not y = y²+12x. The x should be totally replaced with
The second error is where he wrote y = √-11x
The square root of a value must return both negative and positive value not only the positive value. Hence the correct expression should have been y = ±√-11x (Note that the sign ± was introduced)
Third error: Since the value inside the square rot is a negative value hence the value of x must be negative i.e x must be less than zero not greater then. The correct inequality expression should have been <u>x <0</u> and not
x< 0
Answer:
232 square feet
Step-by-step explanation:
The outside dimensions of the yard are 26 ft by 36 ft, so its total area is ...
yard including walk = (26 ft)(36 ft) = 936 ft²
The dimensions of the yard inside the walkway are 22 ft by 32 ft, so that area is ...
yard not including walk = (22 ft)(32 ft) = 704 ft²
The difference in these areas is the area of the walkway:
walkway area = (yard including walk) - (yard not including walk)
= (936 -704) ft² = 232 ft² . . . . area of the walk
_____
Another way to figure this is to consider the length of the centerline of the walkway. That is the perimeter of a rectangle that is 24 ft by 34 ft. The perimeter (centerline length) is 116 ft, and the width of the walk is 2 ft, so its area is ...
(116 ft)(2 ft) = 232 ft²
