The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 
/2!+...........
Given a function f(x)=9/x,a=-4.
We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.
The taylor series of a function f(x)=
Where the terms in f prime 
(a) represent the derivatives of x valued at a.
For the given function.f(x)=8/x and a=-4.
So,f(a)=f(-4)=8/(-4)=-2.
(a)=(-4)=-8/(
=-8/16
=-1/2
The series of f(x) is as under:
f(x)=f(-4)+
=-2+2(x+4)/1!-24/16 /2!+...........
Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 /2!+...........
Learn more about taylor series at brainly.com/question/23334489
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$820.02
Step-by-step explanation:
Since the Taylor family had cash receipts of $876.16 and their excess of cash receipts above cash payments was $56.14.
The total cash payments for the month will be calculated as:
= $876.16 - $56.14
= $820.02
X-5=11
+5 both sides
x=16
hope this helped
My guess is that you're doing the Law of Cosines? You have everything you need for that except the angle theta, which is the thing you need to find. It's set up like this: (8)^2 = (10)^2 + (5)^2 -[2(10)(5)cos A] I used A instead of theta. Doing that math, you have: 64 = 100 + 25 -[ 100 cos A]; 64 = 125 - 100 cos A;
-61 = - 100 cos A; -61 / -100 = cos A; .61 = cos A. Now use your inverse function on your calculator to find cos^-1(.61) and that equals 52.4
Presuming the circle is the whole, 1/4 + 1/2 is 3/4, or 0.75, so it is 75% of the circle.
