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hoa [83]
3 years ago
8

Need help, please and thank you.

Mathematics
1 answer:
Andru [333]3 years ago
7 0

Answer:

The answer to your question is:   (f +g)(x) = 2x² +x -11

Step-by-step explanation:

f(x) = 2x + 3

g(x) = x² + x/2 -7

Find (f+ g)(x)

                    (f+ g)(x) = 2(x² + x/2 -7) + 3    substitution

                     (f +g)(x) = 2x² +x -14 + 3        simplify like terms

                   (f +g)(x) = 2x² +x -11                 result

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3 years ago
-5 < x - 4 greater than it equal 1
saul85 [17]

We have expression -5 < x - 4 \geq 1 that renders the system of inequalities,

\begin{cases}-5 < x - 4 \\x - 4 \geq 1\end{cases}

Which can be simplified to,

\begin{cases}x > -1 \\x \geq 5\end{cases}

So what we get is something greater than -1 and at the same time greater or equal to 5, so the solution is,

x\in(\infty,-1)\cap(\infty, 5]=\boxed{(\infty,5]}.

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Julia has 2 identical rooms in her house. If each room measures 8 fee on one side and 12 feet on another, what is the total area
Ksenya-84 [330]

Answer:


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3 years ago
The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either
kifflom [539]

Hey there,

To solve this problem, let us first define what is mean and median. Mean is the average of all the numbers in the data set while the median is the number in the middle of the data set in ascending order. If we create a box plot for the data of Rome and New York, we can see that there is an outlier in the data for New York. Since New York has an outlier, so the mean is not a good representation on the central tendency of the data. The mean is skewed (distorted) by the outlier. So in this case it is better to use the median. While the Rome data is nice and symmetrical, it does not seem to have an outlier,  so we can use the mean for this data set.

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Write the equation of a circle whose center is at (3,-2) and has a radius of 11.<br>Show your work!
Viefleur [7K]

Answer:

(x - 3)^{2} + (y + 2)^{2} = 121

Step-by-step explanation:

The equation of a circle has the following format:

(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}

In which r is the radius and the centre is the point (x_{0}, y_{0})

In this question:

Center at (3,-2), so x_{0} = 3, y_{0} = -2

Radius 11, so r = 11

Then

(x - 3)^{2} + (y - (-2))^{2} = 11^{2}

(x - 3)^{2} + (y + 2)^{2} = 121

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3 years ago
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