Let's to the first example:
f(x) = x^2 + 9x + 20
Ussing the formula of basckara
a = 1
b = 9
c = 20
Delta = b^2 - 4ac
Delta = 9^2 - 4.(1).(20)
Delta = 81 - 80
Delta = 1
x = [ -b +/- √(Delta) ]/2a
Replacing the data:
x = [ -9 +/- √1 ]/2
x' = (-9 -1)/2 <=> - 5
Or
x" = (-9+1)/2 <=> - 4
_______________
Already the second example:
f(x) = x^2 -4x -60
Ussing the formula of basckara again
a = 1
b = -4
c = -60
Delta = b^2 -4ac
Delta = (-4)^2 -4.(1).(-60)
Delta = 16 + 240
Delta = 256
Then, following:
x = [ -b +/- √(Delta)]/2a
Replacing the information
x = [ -(-4) +/- √256 ]/2
x = [ 4 +/- 16]/2
x' = (4-16)/2 <=> -6
Or
x" = (4+16)/2 <=> 10
______________
Now we are going to the 3 example
x^2 + 24 = 14x
Isolating 14x , but changing the sinal positive to negative
x^2 - 14x + 24 = 0
Now we can to apply the formula of basckara
a = 1
b = -14
c = 24
Delta = b^2 -4ac
Delta = (-14)^2 -4.(1).(24)
Delta = 196 - 96
Delta = 100
Then we stayed with:
x = [ -b +/- √Delta ]/2a
x = [ -(-14) +/- √100 ]/2
We wiil have two possibilities
x' = ( 14 -10)/2 <=> 2
Or
x" = (14 +10)/2 <=> 12
________________
To the last example will be the same thing.
f(x) = x^2 - x -72
a = 1
b = -1
c = -72
Delta = b^2 -4ac
Delta = (-1)^2 -4(1).(-72)
Delta = 1 + 288
Delta = 289
Then we are going to stay:
x = [ -b +/- √Delta]/2a
x = [ -(-1) +/- √289]/2
x = ( 1 +/- 17)/2
We will have two roots
That's :
x = (1 - 17)/2 <=> -8
Or
x = (1+17)/2 <=> 9
Well, this would be your answers.
Answer:
y = –1 + 3x
Step-by-step explanation:
To know which option is correct, we shall use the equation given in each option to see which will validate the table. This is illustrated below:
Option 1
y = –1x + 3
x = –2
y = –1(–2) + 3
y = 2 + 3
y = 5
This did not give the required value of y (i.e –7) in the table.
Option 2
y = 1 + 3x
x = –2
y = 1 + 3(–2)
y = 1 – 6
y = –5
This did not give the required value of y (i.e –7) in the table.
Option 3
y = –3 + 1x
x = –2
y = –3 + 1(–2)
y = –3 – 2
y = –5
This did not give the required value of y (i.e –7) in the table.
Option 4
y = –1 + 3x
x = –2
y = –1 + 3(–2)
y = –1 – 6
y = –7
This gives the required value of y (i.e –7) in the table.
Thus, the equation that matches the table is:
y = –1 + 3x
The area of the figure is 112 square inches.
Step-by-step explanation:
Step 1:
To calculate the value of the composite shape we first divide it into shapes that we know.
In this case, the composite shape consists of a rectangle and a parallelogram attached to it.
If we can calculate the individual areas of the two shapes we should be able to calculate the area of the composite shape.
Step 2:
The rectangle has a length of 22 cm and a width of 8.5 cm. The area of a rectangle is the product of its length and its width.
The area of the rectangle
The area of the rectangle is 187 square cm.
Step 3:
The area of a parallelogram is the product of its base length and its height. The given parallelogram has a base length of 22 cm and a height of 7.5 cm.
The area of the parallelogram 
The area of the parallelogram is 165 square cm.
Step 4:
Now we calculate the area of the entire figure by adding the areas of the rectangle and the parallelogram.
Area of the figure 
So the area of the figure is 352 square cm.
18 * 100 / 36 = 200
<span>36% of 50 is 18</span>
Step-by-step explanation:
4x+y=1-(1)
-6x+y=1-(2)
solve simultaneously
10x =0
X=0/10
X=0
solve for X in (1)
4(0)+y=1
0+y=1
y=1-0
y=1
