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dimaraw [331]
3 years ago
8

2 more then 4 times a number

Mathematics
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

4x+2

Step-by-step explanation:

assuming x represents the unknown number

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Angles α and β are the two acute angles in a right triangle, where α = 5x 3 + 20 and β = 2x 3 + 14. Find α.
Tom [10]
The acute angles of a right triangle are complementary, so
  α + β = 90
  (5x/3 +20) + (2x/3) + 14) = 90 . . . . . . substitute given values
  7x/3 +34 = 90 . . . . . . . . . . . . . . . . . . . collect terms
  7x/3 = 56 . . . . . . . . . . . . . . . . . . . . . . . subtract 34
  x = (3/7)*56 = 24 . . . . . . . . . . . . . . . . . multiply by 3/7

Then the value of α is ...
  α = 5*24/3 +20 = 60
7 0
3 years ago
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Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits
scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

x^{2} + 3x - 8^{- 14} = 0

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

The above solution is for the quadratic equation of the form:

ax^{2} + bx + c = 0  

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

From the given eqn

a = 1

b = 3

c = - 8^{- 14}

Now, using the above values in the formula mentioned above:

x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)

Now, Rationalizing the above eqn:

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}

x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}

Solving the above eqn:

x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}

Solving with the help of caculator:

x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}

The precise value upto three decimal places comes out to be:

x_{1, 1'} = 0.758\times 10^{- 14}

5 0
3 years ago
There are 18 tables at a party each table can seat six people complete the equation to show which operation to use and the total
galina1969 [7]

I can't complete the equation or the sentence because they have not been provided. However, I can write you an equation to model this situation.

Answer:

18x6=108

Step-by-step explanation:

If each table seats 6 people, there are 18 tables, and we are trying to find the total number of seated persons, it can be modeled as such:

tables x capacity of each table=total number of seated persons

plug in:

18x6=108

8 0
3 years ago
How do you journal equipment on hand?
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Answer:

I just looked it up on google and it said to create journal entries...

Step-by-step explanation:

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3 years ago
Suppose we wish to construct the perpendicular bisector of line segment EF. We can correctly begin by placing the compass point
julia-pushkina [17]
- to a point which is more than halfway to the point F. Then draw an arc  around the point. Next place the compass point at  F and,  keeping the same distance between the points of the compass,  draw another arc so as to intersect the first arc at 2 points above and below the line EF. Finally draw a line passing through these 2 points of intersection.  This is the perpendicular bisector of EF.
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2 years ago
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