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3 years ago

Write the proportion 5.5 hours is to 4.5hrs as 7.5 hours in to 60hours

1 answer:

4 0

So the proportion would go as follows

5.5. 7.5
=
4.5. 60

To solve this you just cross muliply and divide.
I hope this helps you

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Don’t know much about geometry

Mariana [72]

Answer:

Step-by-step explanation:

J is a tangent to the circle and it is at right angle,

So applying Pythagorean theorem

HK² = KJ² + HJ²

HK² = 8²+ 15²

HK² = 64 + 225

HK² = 289

HK = √289

HK = 17 mi

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3 years ago

Simplify<br> (-4-8i)-(-1-3i)

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4 years ago

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3 years ago

A sled is being pulled across a floor by two ropes such that the angle between them is 40°. If the forces on the ropes are 100 p

Dafna1 [17]

Answer:

option 4 ⇒ 236 lb.

Step-by-step explanation:

Best explanation of the question is as shown in the attached figure.

we will use the parallelogram method to calculate resultant force.

to get the length of the resultant force ⇒ use the cosines law

The cosine law is a² = b² + c² - 2 * b * c * cos (∠A)

Applying at the question where b = F₁ , c = F₂ and ∠A = ∠x

Given that F₁ = 100 pounds , F₂ = 150 pounds and ∠x = 180° - 40° = 140°

∴ (Resultant force)² = 100² + 150² - 2 * 100 * 150 * cos (∠140) = 55481

∴ Resultant force = √55481 = 235.54 ≅ 236 pounds

The answer is option 4 ⇒ 236 lb.

8 0

3 years ago

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro

Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of $\pi$ , so we use the worst case scenario, which is $\pi = 0.5$

Then

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.03\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.03}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}$

$n = 1067.11$

Rounding up

A sample of 1068 is needed.

8 0

3 years ago