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grin007 [14]
3 years ago
8

A bowl contains 10 quarters, 20 dimes, 15 nickels, and 5 pennies. a coin is selected at random and kept and then a second coin i

s selected at random. which combination would have a probability of 6/49?
Mathematics
1 answer:
DENIUS [597]3 years ago
5 0
In this question, there are a few kinds of the coin with a different value. To answer this question, we need to know the total coin first. The total coin count should be: 10 +20 + 15 +5= 50 coin

In this case, the coin is taken twice, that means the denominator should be 50*49. But in this question, the probablity value is 6/49, so you need to convert it into 50*49 by multiplying the numerator with 50. The value should be:
6/49 *50/50= 300/49*50
The number 300 is multiplication of 20 and 15, that mean the answer should be: 1 dimes and 1 nickles
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Solve by elimination <br><br> { -3x - 10y = -4<br> { x - 5y = 18
mylen [45]


{-3x - 10y = -4} Answer: x = − 10/3y + 4/3

{x - 5y = 18} Answer: x = 5y + 18
5 0
3 years ago
There are four movies showing at the theater, 2/5 of the people bought tickets for the comedy, 1/4 bought tickets for the horror
RUDIKE [14]

Given:

Number of people bought tickets for comedy = \frac{2}{5}

Number of people bought tickets for horror = \frac{1}{4}

Number of people bought tickets for kids movie = \frac{3}{10}

To find the number of people who bought tickets for the action movie.

Let us take,

Total number of tickets = 1

Now,

Total number of tickets for comedy, horror and kids movie are = (\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )

So,

(\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )

LCM of 5,4,10 = 20

= \frac{8+5+6}{20}

= \frac{19}{20}

Rest are action movie's tickets.

Therefore,

Number of action movie tickets = 1-\frac{19}{20}

= \frac{20-19}{20}

= \frac{1}{20}

Hence,

The number of people who bought the tickets for action movie is \frac{1}{20}.

7 0
3 years ago
6x-2x=-4x+2 who is correct spencer or jeremiah
katrin2010 [14]

Answer:

Jeremiah

Step-by-step explanation:

8 0
3 years ago
For the following function y = f(x) = 4x^3 - 5
goblinko [34]

The answer for each of the differentiation are; f'(-6) = 432;  f⁻¹(y) = ∛((y + 5)/4); df⁻¹/dy = 1/432

<h3>How to differentiate functions?</h3>

1) f(x) = 4x³ - 5

We will differentiate it to get;

f'(x) = df/dx = 12x²

f'(-6) = 12(-6)²

f'(-6) = 432

2) We are given the formula;

x = f⁻¹(y)

Thus;

y = 4x³ - 5

4x³ = y + 5

x³ = (y + 5)/4

x = ∛((y + 5)/4)

f⁻¹(y) = ∛((y + 5)/4)

c)  f⁻¹(y) = ∛((y + 5)/4)

df⁻¹/dy = -1/12y²

At f(-6), we have;

df⁻¹/dy = 1/432

Read more about Differentiation at; brainly.com/question/5313449

#SPJ1

6 0
1 year ago
#2: Solve the linear system below using the elimination method. Type your
MariettaO [177]

The given linear system is:

\displaystyle \left \{ {{5x+7y=33} \atop {11x+7y=39}} \right.

The question is asking to solve using elimination. When eliminating, you can either eliminate x or y. In this system, y is much easier to eliminate. The y variable in both equations are 7y. To eliminate, one of them has to be negative, so multiply one of the equations by -1.

I will be multiplying the second equation by -1.

\displaystyle (11x + 7y = 39) \times -1 = -11x-7y=-39

Rewrite the system:

\displaystyle \left \{ {{5x+7y=33} \atop {-11x-7y=-39}} \right.

Subtract:

5x+7y=33\\-11x-7y=-39

5x-11x=33-39\\-6x=-6

Lastly, you need to leave the variable x alone. The variable is currently -6x or -6 times x. To remove it, you need to do the opposite of it, which is dividing by -6.

\displaystyle \frac{-6x}{-6} =\frac{-6}{-6}

\displaystyle x=1

Now that you have the value of x, substitute it into one of the equations to find y. I will be substituting it into the first equation.

5x+7y=33 \rightarrow 5(1)+7y=33

Open the parentheses and multiply:

5+7y=33

Move 5 to the other side to leave the variable alone:

5+7y-5=33-5

You will be subtracting since you're "removing" it by doing the opposite of it.

7y=28

Lastly, divide both sides by 7 to leave y alone.

\displaystyle \frac{7y}{7} =\frac{28}{7}

y=4

\displaystyle (x,y) \rightarrow (1, 4)

The answer is (1, 4).

8 0
2 years ago
Read 2 more answers
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