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grin007 [14]
3 years ago
8

A bowl contains 10 quarters, 20 dimes, 15 nickels, and 5 pennies. a coin is selected at random and kept and then a second coin i

s selected at random. which combination would have a probability of 6/49?
Mathematics
1 answer:
DENIUS [597]3 years ago
5 0
In this question, there are a few kinds of the coin with a different value. To answer this question, we need to know the total coin first. The total coin count should be: 10 +20 + 15 +5= 50 coin

In this case, the coin is taken twice, that means the denominator should be 50*49. But in this question, the probablity value is 6/49, so you need to convert it into 50*49 by multiplying the numerator with 50. The value should be:
6/49 *50/50= 300/49*50
The number 300 is multiplication of 20 and 15, that mean the answer should be: 1 dimes and 1 nickles
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Rico and his friend eat some lasagna. Rico eats 1/9 of lasagna, and his friend eats 1/18 of the lasagna. How much of the lasagna
Blizzard [7]

Answer:

\frac{5}{6} of the lasagna is left

<u>Step-by-step explanation:</u>

Given:

Amount of lasagna Rico eats = 1/9

Amount of lasagna His friend eats = 1/18

To Find:

The amount  lasagna is left =?

Solution:

Total lasagna ate by both Rico and his friend = Amount of lasagna Rico eats +  Amount of lasagna His friend eats

Total lasagna ate by both Rico and his friend = \frac{1}{9} + \frac{1}{18}

Total lasagna ate by both Rico and his friend = \frac{2}{19} + \frac{1}{18}

Total lasagna ate by both Rico and his friend = \frac{3}{18}

Total lasagna ate by both Rico and his friend = \frac{1}{6}

The amount  lasagna is left = 1 - Total lasagna ate by both Rico and his friend.

The amount  lasagna is left = 1 - \frac{1}{6}

The amount  lasagna is left =\frac{6-1}{6}

The amount  lasagna is left =\frac{5}{6}

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fgiga [73]

Answer:

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Step-by-step explanation:

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