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astra-53 [7]
3 years ago
10

The following information is known about a savings account. Time = 6 years Interest rate = 1.9% Principal = $850 What amount of

simple interest will be earned?
Mathematics
2 answers:
kompoz [17]3 years ago
6 0
I = PRT
T = 6
P = 850
I = 1.9% = 0.019

I = (850)(0.019)(6) = 96.90 <==
Sindrei [870]3 years ago
5 0

Answer:

The amount of simple interest would be $ 96.90

Step-by-step explanation:

Given,

Principal amount, P = $ 850,

Time, t = 6 years,

Annual simple interest rate, r = 1.9%,

Thus, the amount of simple interest,

I = \frac{P\times r\times t}{100}

=\frac{850\times 1.9\times 6}{100}

=\frac{9690}{100}

=\$ 96.90

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GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
I WILL MARK AS BRAINLIEST! Solve for Y
zzz [600]

Answer:

See below.

Step-by-step explanation:

Substitute the value for the variable and solve.

a.)

⇒ y = -5(3) + 17

⇒ y = -15 + 17

⇒ y = 2

b.)

⇒ y = 3(3) - 22

⇒ y = 9 - 22

⇒ y = -13

c.)

⇒ y = 2(3) - 25

⇒ y = 6 - 25

⇒ y = -19

d.)

⇒ y = 6(3) - 39

⇒ y = 18 - 39

⇒ y = -21

7 0
3 years ago
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Naddik [55]
I believe the answer is 3 because 1 ⅔ plus 1 ⅔ equals 3 hours so Jesse played basketball.
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At farm 15 of the 20 chickens are hen, what percent of the chicken at the farm are hens?
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Answer:

75%

Step-by-step explanation:

3/4 of the chickens are there. 75% is the same as 3/4.

7 0
3 years ago
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