**Answer:**

D

**Explanation:**

I think putting hyperlink in essential pages is a good idea as it may guide a user

**Answer:**

31 bits.

**Explanation:**

Given, total number of registers = 55

Total instructions = 60

Size of memory = 16 KB

Now, no of registers are 55. We find the next greater or equal power of 2 which is 64 = 26. Hence, 6 bits are required to represent a register operand.

Number of instructions = 60. We find the next greater or equal power of 2 which is 64 = 26. Hence, 6 bits are required to represent a instruction.

Size of memory = 64 KB = 26 * 210 * 23 bits = 219 bits. Hence, 19 bits are required to represent a memory location.

Now, an instruction has 2 parts, opcode and operand. As given there are only two address instructions which are memory operand and register operand.

Hence, total bits would be: 6 bits (opcode) + 6 bits (register operand) + 19 (memory operand) = 31 bits.

**Answer:**

t ensures that you understand what they are saying and you are both on the same track

**Explanation:**

Hi There!

Binary Coding is not for games! If you want to learn coding go on a website called codeacademy!

Hope This Helps!

**Answer:**

5 Launch the Alienware Control Center Press FN + F4 Launches the Alienware Control Center and opens the Theme Manager tab. Keyboard- backlight adjustment Press FN + F5 Press FN + F6 FN + F5 decreases the keyboard-backlight intensity. FN + F6 increases the keyboard-backlight intensity.

**Explanation:**

**Nice Durango**