Differentiate between Scope and Linkage
1 answer:
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Complete Question:
Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 4096-byte cache using 32-bit memory addresses, 8-byte cache blocks and a 8-way associative design. The cache has :
Cache size = 1024 bytes, sets t = 26.8, tag bits, s = 3.2, set index bit =2
Answer:
Check below for explanations
Explanation:
Cache size = 4096 bytes = 2¹² bytes
Memory address bit = 32
Block size = 8 bytes = 2³ bytes
Cache line = (cache size)/(Block size)
Cache line =
Cache line = 2⁹
Block offset = 3 (From 2³)
Tag = (Memory address bit - block offset - Cache line bit)
Tag = (32 - 3 - 9)
Tag = 20
Total number of sets = 2⁹ = 512
Answer: Strong 128-bit encryption.
Explanation: An individual character corresponds to 8 bits . So if there are 16 characters then,
168=128 bits keys
This makes the 128 bit key encryption the strongest amongst all other options.It is strongest because it is almost impossible to decode the 128-character key by any method e.g.-brute-force method.
Other options are incorrect because the characters given by the other bits are as follows: =32 characters
=64 characters
=128 characters
Thus, the strongest character key is of 128 bits. for cipher.