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kati45 [8]
3 years ago
9

X over negative 10 equals 7

Mathematics
1 answer:
alexdok [17]3 years ago
5 0
X/-10 = 7
Step 1: Multiply by -10

(x/-10)*-10 = 7*-10

x = -70
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The estimation of 53 times 39
PilotLPTM [1.2K]
Round each and multiply.
53 rounds down to 50,
39 rounds up to 40.

50*40=2000.
This is close to the actual answer, which is 2067.
8 0
3 years ago
Read 2 more answers
2/5p-3.11=1.13<br> what is p
ivanzaharov [21]

2p-4+16=5p-9

-3p-4+16=-9

-3p-4=16+-9

And if you can solve from there cuz that's a lot of mental math for me. if u see these:() always distribute whatever is before it.

<h2>Did this help?</h2>

6 0
3 years ago
Select the BEST classification for sq. root 25 . A) irrational B) rational C) imaginary Eliminate D) complex
tatuchka [14]

Answer:

B. Rational

Step-by-step explanation:

the square root of 25 is 5. 5 best fits the classification of rational

4 0
3 years ago
-13/10x - 3/2 (11/6x +1)
lukranit [14]
So first simplify 11/6x into 11x/6. Then -13/10x into -13x/10. So you should now have (-13x/10-11x/4)-3/2. Combine the like terms -13x/10 and -11x/4 to get -81x/20 and then with your left over -3/2= -81x/20-3/2
4 0
3 years ago
When using base-10 blocks to divide 452 by 2, how many hundreds flats will be in each equal group? hundreds flats Divide 452 by
daser333 [38]
<h3>Given</h3>

4 hundreds flats; 5 tens rods; 2 ones cubes

<h3>Find</h3>

The number of hundreds flats in each of 2 equal piles

<h3>Solution</h3>

When 4 flats are divided into two equal groups, each group will have ...

... 2 flats

_____

You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.

— — — — —

You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.

8 0
3 years ago
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