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3 years ago

Evaluate 5+3t -10u when t=5 and u=2

Mathematics

2 answers:

Ipatiy [6.2K]3 years ago

4 0

Answer:

5+3t-10ut=5 u=2

5+3t-10 2t=5

5-17t=5

t=0 u=2

Step-by-step explanation:

taurus [48]3 years ago

3 0

The answer is 0

5+3(5)-10(2)
=5+15-20
=20-20
=0

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Write the equation of the line passing through the points (-4,-1) and (2,8)

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<h3>Explanation:</h3>

Calculate the slope with two given coordinate points by using rise over run.

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Slope-Intercept

$y = mx + b \\ m = slope \\ b = y - intercept$

Substitute the value of m in the equation.

$y = \frac{3}{2} x + b$

Substitute any coordinate points that are given or part of the graph in the equation.

$(x_, y) = ( - 4, - 1)$

$- 1 = \frac{3}{2} ( - 4) + b$

Solve the equation for b-term.

$- 1 = \frac{3}{ \cancel{2}} ( \cancel{ - 4}) + b\\ - 1 = 3( - 2) + b \\ - 1 = - 6 + b \\ - 1 + 6 = b \\ 5 = b$

Rewrite the equation by substituting the value of b in the equation.

$y = \frac{3}{2} x + 5$

<h3>Answer</h3>

$\large \boxed{y = \frac{3}{2} x + 5}$

If you have any questions related to the answer, feel free to ask via comment.

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