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3 years ago

What is the difference between and static and current electricity? give an example for each

2 answers:

8 0

Static electricity involves a build-up of electric charge which is released in a single burst. An example would be lightning.
Current electricity is a continuous flow through a conductor, as seen in a wall outlet or a battery.
I hope this helps!

Gnom [1K]3 years ago

4 0

Static electricity is caused by the build up of electrical charges on the surface of objects, while current electricity is a phenomenon from the flow of electrons along a conductor. 2. When objects are rubbed, a loss and/or gain of electrons occurs, which results in the phenomenon of static electricity.

crazy... I just finish taking this class lol

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Explain how the technology of doing math and adding numbers has changed over time this is science

gizmo_the_mogwai [7]

It has changed because earlier in the days people couldn't even figure out if the world was flat or round but now we can add decimals and multiply fractions.

7 0

4 years ago

A force of 400.0N is exerted on a 1,250N car while moving it at a distance of 3.0m. How much work was done on the car?

S_A_V [24]

Answer:

1200 J

Explanation:

Work=force * displacement/distance

Work=400 * 3

Work=1200 J

8 0

3 years ago

The Sun radiates energy at a rate of about 4×1026W. Earth is about 150×106km from the Sun.

sergiy2304 [10]

The average intensity received on the Earth's surface is $12.6*10^{10} W/m^{2}$

$Intensity = Rate of energy radiated/4\pi R^{2}$

where R is the distance of the earth from the sun.

$I=4*10^{26}/4\pi *[150*106*10^{3}]^{2}$

$I=0.12597*10^{12}$

$I=12.6*10^{10} W/m^{2}$

What is the meaning of the intensity of sunlight?

Sun intensity refers to the amount of incoming solar energy, or radiation, that reaches the Earth's surface. The angle at which the rays from the sun hit the Earth determines this intensity.

What is the average intensity received on the Earth's surface?

The average intensity received on the Earth's surface is given by:

$I=rate of energy radiated/4\pi R^{2}$

Thus, the average intensity received on the Earth's surface is $12.6*10^{10} W/m^{2}$

To know more about the intensity received from the sun:

brainly.com/question/29579262

#SPJ1

8 0

1 year ago

1 Verify the identity. Show your work. cot θ ∙ sec θ = csc θ

Fittoniya [83]

To verify the identity, we can make use of the basic trigonometric identities:
cot θ = cos θ / sin θ
sec θ = 1 / cos θ
csc θ = 1 / sin θ

Using these identities:
cot θ ∙ sec θ = (cos θ / sin θ ) ( 1 / cos θ)

We can cancel out cos θ, leaving us with
cot θ ∙ sec θ = 1 / sin θ
cot θ ∙ sec θ = = csc θ

6 0

4 years ago

A. What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound f

nasty-shy [4]

Answer:

A)828.8Hz

B)869.2Hz

Explanation:

Here is a complete question;

What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound from its siren? Speed of sound is 345m/s

b. What frequency does she receive after the ambulance has passed?

Vs= speed of the ambulance

, We convert to m/s for unit consistency

= 115 km/h= 115km× 1000m/1m × 1hr/3600s= 31.94m/s

Dopler effect is when observed frequency of wave changes with respect to the source or when observed moves relative to transmitting medium can be expressed as

f'=[ (v + vo)/(v- vs)]*f

=[ (v )/(v- vs)]*f

The sign vo and vs depends on vthe direction of the velocity

f= frequency of ambulance siren= 753Hz

v= speed of sound in air= 345m/s

Vo= speed of observer= 0

A) we are to determine the f' of ambulance as heard by person as ambulance approaching.

To find the frequency f' observed by the person we use the expresion below

Then substitute the values

f'=[ (v )/(v- vs)]*f

=[ (345)/(345-31.94)]×753

= 828.8Hz

B)What frequency does she receive after the ambulance has passed?

To find the frequency f' observed by the person we use the expresion below

Then substitute the values

f'=[ (v )/(v + vs)]*f

=[ (345)/(345 + 31.94)]×753

= 869.2Hz

4 0

3 years ago