All categories

3 years ago

A force of 400.0N is exerted on a 1,250N car while moving it at a distance of 3.0m. How much work was done on the car?

Physics

1 answer:

S_A_V [24]3 years ago

8 0

Answer:

1200 J

Explanation:

Work=force * displacement/distance

Work=400 * 3

Work=1200 J

You might be interested in

An electron initially 3.00 m from a nonconducting infinite sheet of uniformly distributed charge is fired toward the sheet. The

Nikolay [14]

Answer:

θ = 4.438 * 10^-18 C / m^2

x = 2.0 m

Explanation:

Given:

V_1 = 420 m/s

Δ r = 2.0 m

m_e = 9.109 *10^-31 kg

q_e = 1.602 * 10^-19 C

ε_o = 8.85 * 10^-12

part a

Energy Principle:

E_k,1 - F_e*Δ r = 0

Electric Field strength of infinite sheet

E = θ / 2*ε_o

0.5*m_e* V_1^2 - E*q_e*Δ r = 0

0.5*m_e* V_1^2 - θ*q_e*Δ r / 2*ε_o = 0

θ = (m_e*ε_o* V_1^2) / q_e*Δ r

θ = (9.109*10^-31*8.85*10^-12* 420^2) / 1.602*10^-12*2

θ = 4.438 * 10^-18 C / m^2

part b

Since the Volt potential is constant of a infinite long uniform charge distribution:

0.5*m_e* V_1^2 - E*q_e*Δ r = 0

r_1 = x

r_2 = 0

0.5*m_e* V_1^2 - θ*q_e*x / 2*ε_o = 0

x = (m_e*ε_o* V_1^2) / q_e*θ

x = (9.109*10^-31*8.85*10^-12* 420^2) / 1.602*10^-12*4.438 * 10^-18

x = 2 . 0 m

3 0

3 years ago

How do astronomers explain the orbit of hot jupiters

postnew [5]

The correct answer is D

3 0

4 years ago

How fast does a rocket ship have to go for its length to be contracted to 99% of its rest length?

DaniilM [7]

Answer:

4.2×10⁷ m/s

Explanation:

L = length observed by an observer

L₀ = Proper length

v = Velocity of the rocket ship

Length contraction formula

$L=L_{0}{\sqrt{1-\frac{v^{2}}{c^{2}}}}\\\Rightarrow 0.99=1{\sqrt{1-\frac{v^{2}}{c^{2}}}}\\\Rightarrow \frac{0.99}{1}={\sqrt{1-\frac{v^{2}}{c^{2}}}}\\\Rightarrow 0.99^2=1-\frac{v^{2}}{c^{2}}\\\Rightarrow 0.99^2-1=-\frac{v^2}{c^2}\\\Rightarrow 0.0199\times c^2=v^2\\\Rightarrow v=\sqrt{0.0199}c=v\\\Rightarrow v =\sqrt{0.0199}\times 3\times 10^8\\\Rightarrow v=4.2\times 10^7\ m/s$

The speed of the ship would be 4.2×10⁷ m/s

8 0

3 years ago

The voltage across a membrane forming a cell wall is 84.0 mV and the membrane is 9.40 nm thick. What is the electric field stren

Katarina [22]

Answer:

8.9*10^6 V/m

Explanation:

The expression for electric field strength E is given as

$E=\frac{V}{d}$

where V= voltage

d= distance of separation

Given data

$voltage= 84 mV= 84*10^-^3\\distance= 9.4*10^-^9$

substituting our given data into the electric field strength formula we have

$E= \frac{84*10^-^3}{ 9.4*10^-^9} \\\\E= \frac{84}{9.4} *10^-^3^-^(^-^9^)\\\\E= \frac{84}{9.4} *10^-^3^+^9\\\\E= \frac{84}{9.4} *10^6\\\\E=8.9*10^6 V/m$