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STatiana [176]
3 years ago
15

A baby stroller is a rest on top of a hill which is 10 m high. The stroller and baby have a mass of 20 kg. What is the potential

energy of the baby and stroller?
Formula: PE = m g h (Gravity near earth is 9.8 m/s²)
Physics
1 answer:
Anettt [7]3 years ago
6 0

The potential energy is defined as the energy is contained in the body due to the height over the surface of the earth and it is calculated from the equation

PE=mgh

<em>where:</em>

  • PE: the potential energy in Joules.
  • m: the mass of the body in kg.
  • g: the acceleration due to the gravity in m/s^2
  • h: the height of the body over the earth in meters.

<em>in our problem:</em>

PE=20*9.8*10=1960 J

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Link is a virus don’t click it trust me okay?
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3 years ago
Prove that vf = vi+at.
Gnoma [55]

To make your formula neater:

V_{f}  = V_{i} + a*t

Acceleration is equal to

\frac{velocity}{time} ,

so when you multiply it by time, you will get a velocity.  In fact, you would get the change in velocity, as a*t signifies the acceleration of the object over the time, aka the change in velocity.

The initial velocity plus the change in velocity will equal the final velocity, irregardless if the change in velocity is positive or negative.

Therefore,

V_{f}  = V_{i} + a*t

6 0
3 years ago
What is the efficiency of a device that takes 400J of heat and does 120J of work while giving off 280 J of heat
zubka84 [21]

Answer:

30%

Explanation:

Efficiency = useful work / heat absorbed x 100

= 120/400 x 100

= 0.3 x 100

= 30%

6 0
4 years ago
The radius of the earth is 6380 km and the height of mt.everest is 8848 m. if the value of of acceleration due to gravity on the
Bas_tet [7]

a) 9.80 m/s^2

The acceleration due to gravity at a certain location on Earth is given by

g=\frac{GM}{(R+h)^2}

where

G is the gravitational constant

M is the Earth's mass

R is the Earth's radius

h is the altitude above the Earth's surface

At the top of Mt. Everest,

R = 6380 km = 6.38\cdot 10^6 m

h' = 8848 m

g'=9.77 m/s^2

With

g'=\frac{GM}{(R+h')^2} (1)

At the Earth's surface,

R = 6380 km = 6.38\cdot 10^6 m

h = 0

g = ?

So

g=\frac{GM}{R^2} (2)

By doing the ratio (2)/(1), we find an expression for g in terms of g':

\frac{g}{g'}=\frac{\frac{GM}{R^2}}{\frac{GM}{(R+h')^2}}=\frac{(R+h')^2}{R^2}=\frac{(6.38\cdot 10^6+8848)^2}{(6.38\cdot 10^6)^2}=1.003

And therefore,

g=1.009g'=1.009(9.77)=9.80 m/s^2

b) 519.3 N

The weight of an object near the Earth's surface is given by

W=mg

where

m is the mass of the object

g is the acceleration of gravity at the object's location

In this problem,

m = 50 kg is the mass of the object

g' = 9.77 m/s^2 is the acceleration of gravity on top of Mt Everest

Susbtituting,

W=(50)(9.77)=519.3 N

6 0
3 years ago
When reading a digital volt-ohmmeter (DVOM), you have a reading of 2168 mV, which is the same as:__________
levacccp [35]

Answer:

D, both A and B

Explanation:

2168 mV is the SI unit for potential difference and the Voltmeter.

The primary unit is Volt, represented as V. Due to the fact that there can be a much higher reading, or an even much more smaller one, comes the need for variants of the same unit.

10^-3 is called milli and represented as m

10^3 is called killo and represented as k

10^-6 is called micro and represented as µ

10^6 is called mega and represented as M

and even much higher variants of up to 10^12 and 10^-12

As we can see from the aforementioned example, 10^-3 is milli and represented as m

And our question gave us the unit in mV, which stands for millivolts.

Also, if we look at option B, it states, 2.168 volts. This 2.168 volts is also the same thing as A. Take a look at it this way, I said mV is 10^-3, right?

So, 2168*10^-3 is also 2168/100 which is 2.168. The only difference here is, once we make this conversion from mV, we have to drop the milli tag, because we have already made a conversion, and thus, leave it as V.

2168 mV = 2.168V

Hence why we picked option D, Both A & B as the right one

4 0
3 years ago
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