Answer:
0.249
Explanation:
Perihelion = 4.43 x 10^9 km
Aphelion = 7.37 x 10^9 km
Let e be the eccentricity and a be the length of semi major axis.
The relation between the semi major axis, perihelion and aphelion s given by
Semi major axis = half of sum of perihelion and aphelion
a = 5.9 x 10^9 km
The relation between the perihelion, semi major axis and the eccentricity is given by
Perihelion = a (1 - e)
4.43 x 10^9 = 5.9 x 10^9 (1 - e)
0.751 = 1 - e
e = 0.249
Yes It can because the black light would be considered solar powered
Answer:
4.635 *10^12 Neutrinos
Explanation:
Here in this question, we are to determine the number of neutrinos in billions produced, given the power generated by the proton-proton cycle.
We proceed as follows;
In proton-proton cycle generates 26.7 MeV of energy and in this cycle two neutrinos are produced.
From the question, we are given that
Power P = 9.9 watts = 9.9 J/s
Watts is same as J/s
The number of proton-proton cycles required to generate E energy is N = E / E '
Where E ' = Energy generated in proton-proton cycle which is given as 26.7 Mev in the question
Converting Mev to J, we have
= 26.7 x1.6 x10 -13 J
To get the number N which is the number of proton-proton cycle required, we have;
N = 9.9 /(26.7 x1.6 x10^-13) = 2.32 * 10^12
Since we have two proton cycles( proton-proton), it automatically means 2 neutrinos will be produced.
Therefore number of neutrions produced = 2 x Number of proton-proton cycles = 2 * 2.32 * 10^12 = 4.635 * 10^12 neutrinos
That's pretty easy, have a look :
The only thing you need to do is to find t and the problem is solved.
